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horizontal image display

Discuss horizontal image display in the ASP Programming forum on Dev Shed.
horizontal image display ASP Programming forum discussing Active Server Pages coding techniques and problem solving methods. Use VBScript or Jscript to make dynamic web applications.

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  #1  
Old December 16th, 2003, 10:49 PM
bulletz bulletz is offline
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horizontal image display
hello:
i have an image database, i want my images to be displayed like google when you try to search an image - displays horizontally.

how would i check if the first row already has, say 5 images, and then add another row for the next set of images and so on?

can someone show me a tutorial, an article for this one?

mine doesnt require to search for any images, just concerned with the display.

thanks again
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Old December 17th, 2003, 12:37 AM
pda8333 pda8333 is offline
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hi bulletz,
i have that code somewhere in my pc. let me find first & i'll get back to you.
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Old December 17th, 2003, 12:41 AM
bulletz bulletz is offline
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ok cool, i'll also try to learn the codes.

thanks,
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Old December 17th, 2003, 12:46 AM
pda8333 pda8333 is offline
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I've cut out part of my existing code for you.
Code:
	  <table border="0" cellpadding="2" cellspacing="2" width="100%">
	  	<tr>
		  <td>All My Images</td>
		</tr>
		<tr valign="top">
		 <%
		 ' i is for image to go down to next row
		 Dim i
		 i=0
		 while not rs.eof
		 %>
		  <td width="33%" valign="top" style="border:1px solid #ff9900" height="100%">
		    <!--Start: ind. image table-->
			<table border="0" cellpadding="1" cellspacing="2" height="100%" width="100%">
			  <tr>
			    <td><img src="xxx.xxx" border="0" alt="xxx"></td>
			  </tr>
			</table>
			<!--End: ind. image table-->
		  </td>
		   <%
		   '''' Start: Go Next Row
		   i=i+1
		   ' below means after 3rd image, the 4th image will go to next/new row
		   if i mod 3=0 then
		     response.write"<tr>"
		   end if
		   '' End : Go Next Row
		 rs.movenext
		 wend
		 %>
	    </tr>
	  </table>
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Old December 17th, 2003, 01:17 AM
bulletz bulletz is offline
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thanks for the help again.
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Old December 17th, 2003, 01:19 AM
pda8333 pda8333 is offline
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is this what you are looking for? your welcome.
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