querystring and isarray help

This is really weird, No matter what, i get true for the is array function on a querystring variable, anyone have ideas?

Let's say I pass in "george michaels" or "george" both return true on the is array, yet the A(1) will error if you try and access it on a "george" split on space.




Does anyone have any clue or any advice at all?

alright, now i'm really freaked out, this is hardcoded in:


Both output true....

Well of course it outputs *TRUE*

You know why ???

Because if you read the docs for SPLIT() it says:

Returns a zero-based, one-dimensional array containing a specified number of substrings.


So :

name = "george michaels"

Arr = split(name," ") <---split() will return an array so Arr is an array

response.write IsArray(Arr) <--Will return TRUE because Arr is in fact an array

That's why!

Hope this helps!
Sincerely

Vlince

how would one find out if the split worked then?

I'm passing in a name whether it be first, last, or both, and i need to check to see if the split worked, I guess i'll have to use instr(name, " ")...

stupid split...

I'm sorry, I don't get it :-(

What do you mean by:
---BEGIN QUOTE
how would one find out if the split worked then?
---END QUOTE

You're the programmer so why are you using the Split() function in the first place? If your are then you must have a good reason for no?

Let me ask you this:

Will you *always* have the First Name and Last Name OR can it sometimes be *ONLY* the First Name OR *ONLY* the Last Name OR BOTH

One thing you can try is:

<%
Dim Arr

Arr = Split(Request.Form("Something"))(0)
Response.Write Arr

OR if you want the second element in the array do:
Arr = Split(Request.Form("Something"))(1)
Response.Write Arr


NOTICE the (0) and (1) part!

Hope this helps!
Sincerely

Vlince


%>

Can't say I've ever seen the split function be used the way you're using it, and can't find any documentation on it and it errors on me when i copy your code so i'm not sure what you're getting at.

sorry for being unclear. Yes I am the programmer and am quite aware of why I'm using the split function. Thanks for your help on the IsArray and split, i assumed the split returned a scalar variable if there was no splitting, but it's not as you stated which is why it's always true

first, last, or both names are passed in, i don't know which it will be, it's random, sometimes a person knows their first name, sometimes just the last, sometimes they know a little of each, it's a guess as to what they'll know really.

I have first and last names in a DB and have to parse the name if they give me "geo mi" then i have to search like '%geo%' in the first name field and '%mi%' in the last name field and return the results.

I have it solved by using that instr function i was telling you about.

It just returns 0, the space just doesn't exist in the string and i continue on my merry way, i'm sure you knew that but that's how i'm using it.

regaurds

You are right, using the Split() the way I'm using it isn't documented but it works here copy/paste this example:

<%
Dim str
str = "The dog is red"

Response.Write "-->" & Split(str, " ")(0) & "<--<br>"
Response.Write "-->" & Split(str, " ")(1) & "<--<br>"
Response.Write "-->" & Split(str, " ")(2) & "<--<br>"
Response.Write "-->" & Split(str, " ")(3) & "<--<hr>"
%>

The end result should display:
-->The<--
-->dog<--
-->is<--
-->red<--

Using the Split() the way I'm using it is a shortcut and returns *ONLY* the string I WANT.

Notice that IT DOES NOT return an array since I wanted element (0) for example, so it only returned the string placed a element (0)

Of course if you have a string such as str = "My cat"
and you ask for this:
Response.Write "-->" & Split(str, " ")(2) & "<--<hr>"

This will not work, in fact I think its going to give you an error message since you dont have an element (2) in that string str


Vlince