Actionscript 3.0 > php > mysql (new flash scene after login successful)

Hi guys,

I'm currently having my final year project now and i really need help as i'm new to actionscript 3.0 > php > mysql connection. I feel so ridiculous to not know how to solve this "simple login code". So, here goes...

Currently, after the button is being clicked, a successful message will appear --> print "systemResult=Welcome $username!";.
As you can see from the title of my thread, i want it to go to a new scene instead (in flash). I tried so many ways to do it but sadly, it didn't work. I really need help on this!!! Thanks guys!

[Actionscript]

package actions {

import flash.display.MovieClip;
import flash.events.*;
import flash.net.*;
import flash.text.*;


public class main extends MovieClip {

public function main ():void {

submit_button.buttonMode = true;

submit_button.addEventListener(MouseEvent.MOUSE_DOWN, checkLogin);

username.text = "";
password.text = "*";

}

public function checkLogin (e:MouseEvent):void {


if (username.text == "" || password.text == "") {


if (username.text == "") {

username.text = "Enter your username";

}

if (password.text == "") {

password.text = "Enter your password";

}

} else {

processLogin();

}

}


public function processLogin ():void {

var phpVars:URLVariables = new URLVariables();

var phpFileRequest:URLRequest = new URLRequest("login.php");

phpFileRequest.method = URLRequestMethod.POST;

phpFileRequest.data = phpVars;


var phpLoader:URLLoader = new URLLoader();
phpLoader.dataFormat = URLLoaderDataFormat.VARIABLES;
phpLoader.addEventListener(Event.COMPLETE, showResult);


phpVars.systemCall = "checkLogin";
phpVars.username = username.text;
phpVars.password = password.text;

phpLoader.load(phpFileRequest);

}

public function showResult (event:Event):void {

result_text.autoSize = TextFieldAutoSize.LEFT;


result_text.text = "" + event.target.data.systemResult;

}
}
}

[php] - login.php

<?php

include_once "dbconnect.php";

$username = $_POST['username'];
$password = $_POST['password'];

if ($_POST['systemCall'] == "checkLogin") {

$sql = "SELECT * FROM users WHERE username='$username' AND password='$password'";

$query = mysql_query($sql);

$login_counter = mysql_num_rows($query);

if ($login_counter > 0) {

print "systemResult=Welcome $username!";

} else {

print "systemResult=Invalid User!";

}
}
?>

I don't do fish but you will get answer much quicker by placing this in the correct forum.