Array input problem

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October 13th, 2012, 10:41 AM

Lan07

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Array input problem

Hello everybody i am pretty newbie in c and general on programming so take it easy with me..
So my question is
i have here this code

PHP Code:


		
			
#include <stdio.h>

#include <stdlib.h>



main(){

       int ar[2][2];

       int i,j;

       for (i=0;i<=2;i=i+1)

           for (j=0;j<=2;j=j+1){

               printf(" i = %d j = %d   ",i,j); 

               scanf("%d",&ar[i][j]);

               }

       

       for (i=0;i<=2;i=i+1){

           printf("\n");

           for (j=0;j<=2;j=j+1)

               printf("%d for i= %d, j=  %d     ",ar[i][j],i,j);

       }

       

       

       printf("\nwrong values are ..  %d   %d   %d",ar[0][2],ar[1][2],ar[2][2]);

              scanf("%d",&i);

}

i put in the values 1,2,3 ... to 9 respectivly but it outputs me this h t t p: / / imageshack.us/photo/my-images/840/006503.jpg/

i didnt know any other way to refer people to this image so i had to put this link
Thanks.

October 13th, 2012, 11:30 AM

bdb

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The array (of arrays) defined with

Code:

int ar[2][2];

has 4 elements. Those elements are: ar[0][0], ar[0][1], ar[1][0], and ar[1][1]. You are trying to access elements that do not exist, namely those with 2 as one of the indexes (eg ar[0][2], or ar[2][2]).

Try defining your array with

Code:

int ar[3][3];

October 13th, 2012, 11:31 AM

salem

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> for (i=0;i<=2;i=i+1)
The valid subscripts of ar[2][2] are [0][0], [0][1], [1][0] and [1][1]

You're running off the ends of the array.

Use <, not <= in all your loops.

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October 13th, 2012, 11:50 AM

Lan07

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Really thank you for the help.
BUT

Code:

#include <stdio.h>
#include <stdlib.h>

main(){
       int ar[3][3];
       int i,j;
       for (i=1;i<=3;i=i+1)
           for (j=1;j<=3;j=j+1){
               printf(" i = %d j = %d   ",i,j); 
               scanf("%d",&ar[i][j]);
               }
       
       for (i=1;i<=3;i=i+1){
           printf("\n");
           for (j=1;j<=3;j=j+1)
               printf("%d for i= %d, j=  %d     ",ar[i][j],i,j);
       }
       
       
       printf("\nwrong values are ..  %d   %d   %d",ar[1][3],ar[2][3],ar[3][3]);
              scanf("%d",&i);
}

can you explain me why this one works?(ar[1,2,3,][3] dont exist as you said)
And on the previous code how the computer got access to the ar[0][2] ar[1][2]..
and put those specific (wrong) values, was it random values?
Again thanks for the help.

October 13th, 2012, 12:11 PM

bdb

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> Can you explain why this one works?
Accessing elements that do not exist, in C, is Undefined Behavior, meaning the compiler can do anything: it can complain and stop compilation, it can complain but compile anyway. Furthermore the resulting executable (if any) can do anything: it can crash, it can work with apparent errors, or it can work as you would expect (the most difficult UB to catch).

To answer your question: that one works because you were unlucky.

I see you changed the loop to start accessing the array elements at index 1 (it was index 0 in your previous post). In C, array indexes start at 0. Your first post was correct in this regard.

October 13th, 2012, 12:47 PM

b49P23TIvg

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How many non-negative integers are there less than 3 ?

0 1 2

That's right, 3 of them.

Less than n where n is a non-negative integer?

That's right, n of them.

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Array input problem

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