Array with functions

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June 4th, 2003, 09:16 PM

xdrunkcowx

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Array with functions

hello i put this code in the compiler (Dev-C++ 4.0):

PHP Code:


		
			
#include <iostream>

using namespace std;

int main()

{

    int i;

    int x;

    int a;

    char square[25];

    square[0] = 'a';

    square[1] = 'b';

    square[2] = 'c';

    square[3] = 'd';

    square[4] = 'e';

    square[5] = 'f';

    square[6] = 'g';

    square[7] = 'h';

    square[8] = 'i';

    square[9] = 'j';

    square[10] = 'k';

    square[11] = 'l';

    square[12] = 'm';

    square[13] = 'n';

    square[14] = 'o';

    square[15] = 'p';

    square[16] = 'q';

    square[17] = 'r';

    square[18] = 's';

    square[19] = 't';

    square[20] = 'u';

    square[21] = 'v';

    square[22] = 'w';

    square[23] = 'x';

    square[24] = 'y';

    square[25] = 'z';

    void read () {

    for (i=0; i<=25; i++){

    cout<<square[i];

    }

    }

    for (a=0; a<=25; a++){

    for (x=0; x<=a; x++){

    read();

    }

    cout<<"\n";

    }

}

and i get a **** load of errors like:
35 test22.cpp
parse error before `{'
36 test22.cpp
parse error before `)'

then i just get a lot of sntax errors like
40 test22.cpp
syntax error before `<='

if i take out the read fuction and the calling of the read function it all compiles fine.. could someone please help me figure out what im doing rong.. thanks,
Jordan

June 4th, 2003, 10:10 PM

Scorpions4ever

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You can't declare one function within another in C. That's the problem. You'd have to declare read() outside main(). Since read() accesses an array, you can either
(a) declare the array as a global
(b) modify the read() function to accept an array pointer as a parameter.

Hope this helps

June 5th, 2003, 10:04 AM

Analyser

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On a different note, square should actually be defined as char square[26], instead of char square[25].

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June 6th, 2003, 12:39 AM

TechNoFear

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char sSquare[27];//extra space for the '\0'

sprintf(sSquare,"abcde...........xyz");

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Array with functions

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