C - Programming. Assigning an integer to a character array

root@galaxian:~# gcc -o from_octal_to_string from_octal_to_string.c

from_octal_to_string.c: In function `convert_from_octal_to_string':

from_octal_to_string.c:17: incompatible types in assignment

Line 17 is a problem

How do I assign a number 144 to a character array ?

================================
1 #include <stdio.h>
2
3 convert_from_octal_to_string()
4 {
5 unsigned long octal_long;
6 int var_oct = 1015;
7 int var1 = 0;
8 char array_char[4];
9
10 var1 = (var_oct - 7) / 7; /* equal 144 */
11 printf ("var1 = %d\n", var1);
12
13 array_char = var1; --> THE PROBLEM IS HERE
14
15 /*convert from octal value to string. 144 is a d */
16 octal_long = strtoul (var1, NULL, 8);
17 printf ("octal_long = %c\n", octal_long);
18 }
19
20/********************************************/
21
22 main()
23 {
24 convert_from_octal_to_string();
25 }

You're trying to assign an integer to character array on Line 13.

Can't you just use sprintf()?

Here is a little test I ran:



That's if you actually need to save the data from val1 into array_char. If you just needed to print it out once or so, just use printf():

I'm not sure what you're trying to do with the rest of your code. Remember, every single number stored in a computer is in binary (even BCD and packed decimal, though those are specially-formatted binary numbers). It's only the human-readable representations of those binary numbers that end up being octal or hexadecimal or decimal or sexagesimal (base-60, which we use all the time). So the very basis of what you are doing in that program seems very suspect to me.

However, if you want to convert a binary number to its octal representation, then that would be with the %o family of format specifiers (%o for unsigned int, %ho for unsigned short, %lo for unsigned long):

BTW, I hadn't used the strto** family of functions before, so I didn't know before that strtoul enables you to convert a string representing a number of any base. Cool.

I think you are assigning an int to a constant pointer since the name of an array is a constant pointer...