In most *NIXES, there's a time_t type that is supposed to be used for keeping information about dates and times (Currently time_t is the same as unsigned int in most cases, but that may change in the future, hence you're always advised to declare the variables as type time_t instead of int for portability). Getting the current time uses code something like this:
Code:
#include <time.h>
int main() {
time_t current;
current = time(NULL);
return 0;
}
In Linux, the time_t type is acually a count of the # of seconds since 1/1/1970. Since a day has 86400 seconds, so your date_add function would look something like this:
Code:
time_t date_add(time_t current, int nDays) {
return current + (nDays * 86400);
}
Similarly, you can write a date_sub function which subtracts the required number of seconds. To find the difference between two date/times, you can use the
difftime() function
Now to convert your date/time to ascii, you could use the functions ctime() or asctime(). Check the man pages for this Also you might need to use the localtime() function to convert your date/time to your local time zone first. The localtime function is also useful if you want to break up the time into month, day, year, hour, min etc. So your code could look something like this:
Code:
#include <stdio.h>
#include <time.h>
int main() {
time_t current;
struct tm *timeptr;
current = time(NULL);
printf("Date and Time are %s\n", ctime(¤t));
printf("Date and Time are %s\n", asctime(localtime(¤t)));
timeptr = localtime(¤t);
printf("Date is %d/%d/%d\n", timeptr->tm_mon+1, timeptr->tm_mday, timeptr->tm_year + 1900);
return 0;
}
[edit]
Looks like there's a bug in the forum software and the code's not rendering correctly above. The part that looks like ¤t should really be & current (remove the space in between)
[/edit]
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April 19th, 2002, 11:41 AM
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