how to read individual characters

if the user inputs the number 12345

how would i calculate 1+2+3+4+5
Basically my question is: is there a way for the c program to read the number 12345 seperately as 1,2,3,4 and 5?

would i use cin.get()?

I tried the while statement: while ( (digit = cin.get() ) number <=5) {

but that doesnt work
can someone help me?

read in the whole line as text and then parse the string. Make sure each char is a digit then keep a running total.

im still a beginner and i have no idea what ur talking about!
please clarify

You say "c program", but cin is a C++ feature that isn't in C. In C++, you would use cin.get() to get individual characters; in C, you would use getc(stdin) or getchar(). (For practical purposes, the C/C++ variants have the same functionality; it's just the name that's different.)

Also, isn't a valid C++ (or C) expression. What is "number" supposed to be?

// Lab6a

//Program that uses a counter-controlled while loop to input the 5
//digits of a 5 digit number (assume no spaces will appear between
//digits) and then prints the sum of the digits

#include <iostream>

using std::cout;
using std::cin;
using std::endl;

int main ()
{
int numbers = 1;
int sum;

int A;
int B;
int C;
int D;
int E;

while ( numbers <= 5 ) {
cout << "Enter a five digit number: " <<endl;

cin >> A;
numbers = numbers +1;

cin >> B;
numbers = numbers +1;

cin >> C;
numbers = numbers +1;

cin >> D;
numbers = numbers +1;

cin >> E;
numbers = numbers +1;


sum = A + B + C + D + E;
cout << " sum is "<< sum << endl;

}

return 0;
}

Nunki means to read in the whole thing so you have a string of characters, 12345. Then point a pointer at the first one, convert it to a number (it's a code representing a character digit), add it to a total that starts off at zero, then point to the next one and do the same thing. Continue until you run out of stuff to process, and you'll have a running total. Refer to a ASCII table to see what actual numeric value the character codes have. '1', for instance, is 49, '2' is 50, and so forth. You'll have to subtract out that offset to get the actual quantitative value. You might want to review the "Convert a character to binary" thread.

Isnt there an easier way...im still not understanding what ur talking about. I am only a beginner. Thanks for ur effort and help though, A LOT!

amangarg,

There's no need to use a while loop, since it always loops exactly once.

The line

cin >> A;

will read the entire 5-digit number into A. You need to use cin.get(), not the >> operator, to get individual characters:

They were suggesting a more powerful and general paradigm for processing input. Frankly, in your situation, it's big-time overkill, since the normal cin functions do what you want. If I were you, I would forget about what they said until you have your feet firmly on the ground of C++ (which you will); you'll get to it eventually.

Lux is showing you the best looking and easiest way to do it. So listen and pay attention instead of whining in between posts. That should be fine to turn in. If someone asks you what happens if they type in 12Z45, just tell 'em you dunno, you're working on that :-).

I personally just never use cin / cout . (Do NOT, I repeat, NOT look at my posts!

Actually I need a while loop in the program as the program assignment. THe following program still does not work


#include <iostream>

using std::cout;
using std::cin;
using std::endl;

int main ()
{
int numbers = 1;
int sum;

char digit;

while ( (digit = cin.get() ) numbers <= 5 ) {
cout << "Enter a five digit number: " <<endl;

cin >> digit;
numbers = numbers +1;

cin >> digit;
numbers = numbers +1;

cin >> digit;
numbers = numbers +1;

cin >> digit;
numbers = numbers +1;

cin >> digit;
numbers = numbers +1;


sum = digit + digit + digit + digit + digit;
cout << " sum is "<< sum << endl;

}

return 0;
}

You need to be adding to sum after every cin i.e. after you increment numbers add to sum. Secondly put the cout above the while, and the while loop should only run to 5. Ditch digit = cin.get(). Your on the right track, just some minor syntax and thought glitches. When you do cin>>digit, it overwrites what was in it before right? So thats why you need to take that value and add it to the running sum, because when you do another cin>>digit, it wipes out the old value, or as DaWei_M would say "the old value goes right to davy jones locker".

On another note I would recommend you take advantage of the while loop. You really only need to grab a char once in the while loop and increment the counter, because as it stands your while loop only runs once.

Something like

This isn't too efficient. First of all, the amount of letters have to be declared in the beginning of the program. Second, the user has to enter each digit seperately, thus making this program a strong proponent of great confusion. The user will not think of this as very clever. I will post this code exactly 1 day later.

this is probably the solution you need. i would just like to point out that this is the second assignment for which you will be turning in someone else's work. are you learning anything?