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  #1  
Old October 18th, 2002, 05:20 AM
Lii Lii is offline
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need help with manipulating user input

Suppose a user enters this

cin >> 23,4545,576,43,4

Is there a way I can capture the input and split it into the individual numbers and put them in an integer array in C++. I know there is getline() but it does not allow you to keep the elements as integers. Help will be greatly appreciated.

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  #2  
Old October 18th, 2002, 07:49 AM
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You know you can always use atol() or atoi() to convert a character to a long or integer values.

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  #3  
Old October 18th, 2002, 10:35 PM
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Are there always going to be a fixed number of elements in the input?

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Old October 19th, 2002, 02:26 PM
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yeah, the user always specifies how many elements they are going to enter.

Thanks Onslaught those functions will come in handy!! )

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Old October 19th, 2002, 08:20 PM
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You could then possibly use cin in a loop and use a char field to extract the commas out of the way, something like this:
Code:
#include <iostream>
int main(void) {
  int nCount, i;
  cout << "Enter number of elements: ";
  cin >> nCount;
  
  int *nElems = new int[nCount];
  char cDummy; 

  cout << "Enter elements separated by commas below\n";
  for (i=0; i < nCount-1; i++)
    cin >> nElems[i] >> cDummy;
  cin >> nElems[nCount - 1];

  // Now print out the numbers entered
  for (i = 0; i < nCount; i++)
    cout << i << " => " << nElems[i] << "\n";

  // clean up
  delete [] nElems;
  return 0;
}

Hope this helps!

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  #6  
Old October 31st, 2002, 10:57 AM
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Here's a slightly more elegant solution:

Code:
int* digit;
int digitno;
string userinput;

cout << "Enter your number: ";
cin >> userinput;

digit = (int*)calloc(userinput.length() + 1, sizeof(int));

digitno=0;
for(int i=0; i < userinput.length(); i++) {
  if (isdigit(userinput[i]))
    digit[digitno++] = atoi(userinput[i]);


That way the user doesn't need to know how many digits ahead of time.
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  #7  
Old October 31st, 2002, 12:58 PM
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ClayDowling, the code you've presented won't quite work because atoi works on const char *, not char. So atoi(userinput[i]) won't work. Also it appears that your code is attempting to put each digit in a separate element of the array, which wasn't the original requirement. Interesting approach though

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Old October 31st, 2002, 01:39 PM
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Scorpion, thanks for the heads up. Compiler would have caught that in time. So we'll change the last line of the code a bit:

Code:
digit[digitno++] = userinput[i] - '0';

Last edited by ClayDowling : October 31st, 2002 at 01:42 PM.

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  #9  
Old October 31st, 2002, 01:43 PM
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Actually I think it was individual numbers rather than individual digits, with the numbers being separated by commas on the input line.

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