Ounter of 6 bit and i need a counter of 48 bit

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October 19th, 2012, 05:17 AM

Hunain Hafeez

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Join Date: Oct 2012

Posts: 2

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Ounter of 6 bit and i need a counter of 48 bit

this code is working for a counter of 6 bit and i need a counter of 48 bit ... if u have time kindly try it..... i try alot but not succeed

#include<stdio.h>
#include<stdlib.h>
#include<float.h>
#include<math.h>
#include <time.h>
#include <cstdlib>
#include <iostream>
#include<stdint.h>
#include<conio.h>

int main()
{

int a[64][6];
int i,j,k,d,c,n;
for(k=0;k<64;k++) //6 digit binary so 2^6 =64 is no: of combinations
{
for(j=0;j<6;j++)
{
a[k][j]=0;
}
}
for(i=0;i<64;i++)
{
n=i;
for(j=5;j>=0;j--)
{
while(n!=0)
{
a[i][j]=n%2;
j--;
n=n/2;
}
}
}
for(k=0;k<64;k++)
{
for(j=0;j<6;j++)
{
printf("%d",a[k][j]);
}
printf(" .................%d\n",k);
}
//printf("\n **** KHATAM SHo ****\n");
getch();
return 0;

}

October 19th, 2012, 05:30 AM

salem

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Edit your post, and put [code][/code] tags around the code.

It should look like this when you're done.

Code:

#include <stdio.h>
int main ( ) {
    // code code code
    return 0;
}

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October 19th, 2012, 06:12 AM

Hunain Hafeez

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Join Date: Oct 2012

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Code:


#include<stdio.h>
#include<stdlib.h>
#include<float.h>
#include<math.h>
#include <time.h>
#include <cstdlib>
#include <iostream>
#include<stdint.h>
#include<conio.h>

int main()
{

 int a[64][6];
 int  i,j,k,d,c,n;
for(k=0;k<64;k++) //6 digit binary so 2^6 =64 is no: of combinations 
{
    for(j=0;j<6;j++)
    {
        a[k][j]=0;
    }
}
for(i=0;i<64;i++)
{
    n=i;
    for(j=5;j>=0;j--)
    {
        while(n!=0)
        {
            a[i][j]=n%2;
            j--;    
            n=n/2;      
        }
    }
}
for(k=0;k<64;k++)
{
    for(j=0;j<6;j++)
    {
        printf("%d",a[k][j]);
    }
    printf(" .................%d\n",k);
}
//printf("\n **** KHATAM SHo ****\n");
    getch();
    return 0;
    
}

October 19th, 2012, 07:33 AM

salem

Contributed User

Join Date: Jun 2005

Posts: 3,835

Time spent in forums: 2 Months 3 Weeks 2 Days 16 h 3 m 48 sec
Reputation Power: 1774

Quote:

#include<stdio.h>
#include<stdlib.h>
#include<float.h>
#include<math.h>
#include <time.h>
#include <cstdlib>
#include <iostream>
#include<stdint.h>
#include<conio.h>

First, decide whether you're writing C or C++.
Including a whole mess of header files from all over the place doesn't help.

> int a[64][6];
> int i,j,k,d,c,n;
Pick meaningful variable names.
Aside from i,j for loop variables, everything else should have a more descriptive name.

Also, how does 64 and 6 relate to your requirement for 48 bits?

Which compiler are you using?
I note from your use of <iostream> that it seems to be something reasonably modern.

Perhaps you could try to see if
unsigned long long var;
is accepted by your compiler.

On most machines, this would be a 64-bit variable, and would thus solve any messy emulation.

Ounter of 6 bit and i need a counter of 48 bit

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