Pointer

#define MAXLEN 50
char *pMsgString = {"HDLC defines three different data.......................................... "};
void split(char *pMessage)
{
int slen, leng;

char *pE, *pF;

slen = strlen(pMessage) ;
pE = pMessage;
do
{
pF = pE;
leng = slen > MAXLEN ? MAXLEN : slen ;

pE = pF + leng;

while (*pE != ' ')
{
if (*pE == 0)
break ;
pE--;
leng-- ;
}

leng==pE-pF ;

printf("%*.*s\n", leng, leng, pF) ;
getch();

display(pF);
slen -= leng;
} while(slen>0);

}
this function is suppose to split my msg into 50 characters by 50 chars and display it. But i wish to store the segmented message into another pointer rather than directly displaying it. is there a way to do it?
thanx for helping

You can create a pointer with new and for the char array size use the length of the char pointer you want to copy + 1. Then, you can use strcpy() to copy one char pointer to the other:

pnew_string = new char[strlen(pstring) + 1];
strcpy(pnew_string, pstring);

pstring must contain a c-style string, i.e. one that's terminated with \0. (include <cstring>)

If your pointer doesn't contain a c-style string, you can use a for-loop to copy one character at a time using pointer notation:

pnew_string= new char[pstring_length];
for(int i=0;i<pstring_length; i++)
{
*(pnew_string + i) = *(pstring + i);
}