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#1
February 25th, 2003, 08:44 AM
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Return Value
Hello!
I have question regarding the return value of a function. I have two separate C files In file1 I have: double value = getValue(); printf("Value: %f\n", value); In file2 I have a global defined as: double v = 2; Also in file2 I have a function defined as: double getValue() { printf("V: %f\n", v); return v; } When this function gets called from file 1, it prints out the value correctly in getValue(), however, when I print out the return value, I get an incorrect value. How can this be happening? Thank-you
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#2
February 25th, 2003, 11:36 AM
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these two pieces of code in seperate files:
Code:
/* file 1 */
#include <stdio.h>
#include "file2.c"
main()
{
double value = getValue();
printf("Value: %f\n", value);
}
Code:
/* file 2 */
#include <stdio.h>
double v = 2;
double getValue()
{
printf("V: %f\n", v);
return v;
}
result in: Code:
V: 2.000000 Value: 2.000000 which is what you were expecting, i think. could the problem be something to do with the include file 2 part? by the way, when i compiled these 2 files i only needed to specify file1.c in the compilation command, as file2.c is linked to and included within file1. h.t.h. if it doesn't help, you need to post what your actual wrong results were and a description the file setup i think.
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#3
February 25th, 2003, 01:27 PM
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>> #include "file2.c"
This is valid, but bad programming practice. We've had quite a few threads about this topic here. Best way to handle it is to make a file2.h file to contain the prototype of the function in file2.c: Code:
/* file2. h*/
double getValue();
/* file2.c */
#include <stdio.h>
#include "file2.h"
double v = 2;
double getValue()
{
printf("V: %f\n", v);
return v;
}
/* file1.c */
#include <stdio.h>
#include "file2.h"
int main(void)
{
double value = getValue();
printf("Value: %f\n", value);
return 0;
}
Hope this helps!
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