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  #1  
Old December 26th, 2012, 05:43 AM
jessy.lailah jessy.lailah is offline
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Run-Time Check Failure #2 - Stack around the variable 'temp2' was corrupted.

Can anyone tell me what "Run-Time Check Failure #2 - Stack around the variable 'temp2' was corrupted." means?
my code works , the only problem is that after it's completely finished it crashes with the above error.

this is the code:

#include <stdio.h>
#define N 3

void resetMatrix(int arr[][N], int size);
void printLine(int size);
void printRow(int arr[][N],int size);
void printGame(int arr[][N], int size);
int check_rows(int arr[][N],int size);
int check_col(int arr[][N], int size);
int check_diagonal(int arr [][N],int size);
int check_game(int arr[][N], int size);
int check_end(int arr[][N],int size);
int inputCheck (int arr[][N],int size, int num1 ,int num2);

//------------------------------------------------------------------

void resetMatrix(int arr[][N], int size)
{
int i,j;
for(i=0; i<size; i++)
for(j=0; j<size; j++)
arr[i][j]=' ';
}
void printLine(int size)
{
int i;
printf("+");
for(i=0; i<size; i++)
printf("---+");
printf("\n");
}
void printRow(int arr[][N],int size)
{
int i,j;
printf("|");
for(i=0; i<size; i++)
for(j=0; j<size; j++)
printf(" %c |",arr[i][j]);
printf("\n");
}
void printGame(int arr[][N], int size)
{
int g,j;
printf("\n");
for(g=0; g<size; g++)
{
printLine(size);
printf("|");
for(j=0; j<size; j++)
printf(" %c |",arr[g][j]);
printf("\n");
}
printLine(size);
}
int check_rows(int arr[][N],int size)
{
int i,j,row=0;
for(i=0; i<size; i++)
{
row=0;
for(j=0; j<size; j++)
row=row+arr[i][j];
if(row==(88*size))
{
printf("Player 1 wins.\n");
return 0;
}
else if (row==(79*size))
{
printf("Player 2 wins.\n");
return 0;
}
}
return 1;
}
int check_col(int arr[][N], int size)
{
int i,j,col=0;
for(j=0; j<size; j++)
{
col=0;
for(i=0; i<size; i++)
col=col+arr[i][j];
if(col==(88*size))
{
printf("Player 1 wins.\n");
return 0;
}
else if (col==(79*size))
{
printf("Player 2 wins.\n");
return 0;
}
}
return 1;
}
int check_diagonal(int arr [][N],int size)
{
int i,j,diag=0,diag2=0;
for(i=0,j=(size-1); i<size; i++,j--)
{
diag2=diag2+arr[j][i];
if(diag2==(88*size))
{
printf("Player 1 wins.\n");
return 0;
}
else if(diag2==(79*size))
{
printf("Player 2 wins.\n");
return 0;
}
}
for(j=0; j<size; j++)
{
diag=diag+arr[j][j];
if(diag==(88*size))
{
printf("Player 1 wins.\n");
return 0;
}
else if(diag==(79*size))
{
printf("Player 2 wins.\n");
return 0;
}
}
return 1;
}
int check_game(int arr[][N], int size)
{
if(check_diagonal(arr,size)==0||check_rows(arr,size)==0||check_col(arr,size)==0)
return 0;
else return 1;
}
int check_end(int arr[][N],int size)
{
int i,j,flag=0,flag2=0;
for(i=0; i<size; i++)
for(j=0; j<size; j++)
{
if(arr[i][j]==' ')
flag2++;
else flag++;
}
if (flag==(N*N))
return 0;
if (flag2>0)
return 1;
return 2;
}
int inputCheck (int arr[][N],int size, int num1 ,int num2)
{
if(num1>(size-1)||num1<0||num2>(size-1)||num2<0||arr[num1][num2]!=' ')
{
printf("Wrong input, please try again: ");
return 0;
}
return 1;
}
//------------------------------------main----------------------------------------------------
void main ()
{
int matrix[N][N]={0};
char temp1,temp2,X=88,O=79;
resetMatrix(matrix, N);
while (check_end(matrix,N)==1)
{
printf("Player 1 turn:\nPlease choose square: ");
do
{
scanf("%d%d",&temp1,&temp2);
}
while (inputCheck (matrix, N, temp1, temp2)==0);
matrix[temp1][temp2]=X;
printGame(matrix, N);
if(check_game(matrix, N)==0)
return;
if(check_end(matrix, N)==0)
{
printf("There is no winner.");
return;
}
printf("Player 2 turn:\nPlease choose square: ");
do
{
scanf("%d%d",&temp1,&temp2);
}
while (inputCheck (matrix, N, temp1, temp2)==0);
matrix[temp1][temp2]=O;
printGame(matrix, N);
if(check_game(matrix, N)==0)
return ;
if(check_end(matrix,N)==0)
{
printf("There is no winner.\n");
return ;
}

}
}

Thanks in advance

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  #2  
Old December 26th, 2012, 05:58 AM
jessy.lailah jessy.lailah is offline
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Join Date: Dec 2012
Posts: 2 jessy.lailah User rank is Just a Lowly Private (1 - 20 Reputation Level) 
Time spent in forums: 21 m 11 sec
Reputation Power: 0
Never mind , found the problem

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