Simple printf statment not working

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October 1st, 2012, 11:24 AM

LightningBlade

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Simple printf statment not working

I have not been programming in C very long, but for some reason I can't even get a simple printf statement to work, even though it looks identical to another statement that does work.

Code:

#include <stdio.h>

int main() {
printf("Hi\n");
return 0;
}

When I compile I get no error (compiling on Linux with gcc).
When I run it there is no output at all. It returns to the next line waiting for another command (back to the ~$ prompt)

Any ideas as to what I'm doing wrong? I can't figure it out.

October 1st, 2012, 11:34 AM

b49P23TIvg

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Code:

$ cat > c.c
#include <stdio.h>

int main() {
printf("Hi\n");
return 0;
}
$ gcc c.c
$ ./a.out
Hi
$

by the way, I recommend puts("Hi") rather than the long winded and inefficient printf("this string has to be scanned for format specifiers\n")

Comments on this post

LightningBlade agrees!

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October 1st, 2012, 11:41 AM

LightningBlade

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Quote:

Originally Posted by b49P23TIvg

by the way, I recommend puts("Hi") rather than the long winded and inefficient printf("this string has to be scanned for format specifiers\n")

I'm actually trying to test an output for another program I'm writing, and I was putting it into a separate program (the other one won't compile yet) and it is a little more complex than just "Hi", but for some reason I couldn't get it to print anything, and so I tried several different things, and even "Hi" wouldn't print. So, that's when I came with the question.

--Edit--
I tried compiling it exactly like you did ($ gcc c.c) and it works. When I try compiling it like this ($ gcc -o test c.c) it doesn't. Is this normal, or do I have to compile to a.out all the time?