Telecomunication program - pb with how to verifie that a nbr is included in an array-

#include <stdio.h>
#include <stdlib.h>
int number,n,friendnumber,amountofmoney;
int operatorr;
 
int main()
{
do
    {
    printf("Enter your number please :\n");
    scanf("%d",&number);
    printf("You are now using the operator: 123\n");
 
    printf("press 2 to choose how to buy and 3 to talk to an agent and 1 to send a default msg and 0 if you want to exit ");
    scanf("%d",&n);
 
 
        if(n==2)
    {
 
          printf("\nyou will buy credit, enter your amount of money :");
          scanf("%d",&amountofmoney);
 
    }
    else if  (n==3)
    {
        printf("\nyou are now talking to an agent press 1 to hung out");
        scanf("%d",&n);
    }
    else if (n==1)
    {
        printf("\nif you want to send a default message to a friend enter his number : ");
        scanf("%d",&friendnumber);
        if (friendnumber[&number])
        {
            printf("Hi, how are you ?");
            printf("\nI need you in emergency");
            printf("\nlet's meet tonight");
            printf("\nI will be there ASAP");
        }
       else
       printf("\nyou're user is not using the same operator as you ");
    }
    }
    while (n!=0);
 
return 0;
}

#include <stdio.h>
#include <stdlib.h>
int number,n,friendnumber,amountofmoney;
int operatorr,foperatorr;
long a,b,c,d,e,f;
int x;

char opa[]="operator 1";//number beginning with 100
char opb[]="operator 2";//number beginning with 200

int main()
{   printf("Enter your 7 digit number please :\n");
    scanf("%d",&number);
    a=(number/1000000);
    b=(number/100000)-(a*10);
    c=(number/10000)-(a*100)-(b*10);
    {{if(a==1)
    {
        if(b==0)
        {
            if(c==0)
                {operatorr=1;
                printf("you are using operator %d\n\n",operatorr);}
        }
    }}

    {
    if(a==2)

    {
        if(b==0)
        {
            if(c==0)
                {operatorr=2;
                printf("you are using operator %d\n\n",operatorr);}
        }
    }
    }}
{do
    {

    printf("press 2 to choose how to buy and 3 to talk to an agent and 1 to send a default msg and 0 if you want to exit ");
    scanf("%d",&n);


        if(n==2)
    {

          printf("\nyou will buy credit, enter your amount of money :");
          scanf("%d",&amountofmoney);

    }
    else if  (n==3)
    {
        printf("\nyou are now talking to an agent press 1 to hung out");
        scanf("%d",&n);
    }
    else if (n==1)
    {
        printf("\nif you want to send a default message to a friend enter his number : ");
        scanf("%d",&friendnumber);
        d=(friendnumber/1000000);
        e=(friendnumber/100000)-(d*10);
        f=(friendnumber/10000)-(d*100)-(e*10);
    {{if(d==1)
    {if(e==0)
    {if(f==0)
    foperatorr=1;}}}
    {if(d==2)
    {if(e==0)
    {if(f==0)
    foperatorr=2;}}}}

        {if(foperatorr==operatorr)
        {printf("you and you're friend are on the same operator.");
        printf("\nPlease choose from the following default messages.\n\n");
        printf("1. Hi, how are you ?");
        printf("\n2. I need you in emergency");
        printf("\n3. let's meet tonight");
        printf("\n4. I will be there ASAP");
        scanf("%d",&x);
        printf("\nmessage number %d sent to your friend.\n",x);}
        else
       printf("\nyou're friend is not using the same operator as you\n ");
    }}}
    while (n!=0);
    }
}