What is wrong;

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October 21st, 2012, 07:16 AM

Giorgos

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What is wrong;

hi to all,
can someone help me
to find out what is wrong into this code and i cannot print the x;

Code:

# include <stdio.h> # include <stdlib.h> # include <iostream> # include<conio.h>   main() {     int p[6];       int i,c;       int x;        printf("Give me 6 number\n");       for(i=0;i<6;i++);       scanf("%d",&p[i]);       printf("%d\n",p[i]);       x=p[1]+p[2];       printf("%d\n ",x);       system("pause");       }

Comments on this post

salem disagrees: Pay attention to formatting before you press 'submit'. No one cares to look at code all on one line

October 21st, 2012, 07:31 AM

G4143

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Join Date: Oct 2012

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Take a close look at this line

Code:

for(i=0;i<6;i++);

Please note the semi-colon.

Also a note on proper syntax. The main function returns an integer.

Code:

int main()
{
/*C++ implies return 0 while C requires a return 0*/
}

October 21st, 2012, 07:35 AM

Giorgos

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Quote:

Originally Posted by G4143

Take a close look at this line

Code:

for(i=0;i<6;i++);

Please note the semi-colon.

it must be i<5 right ? but the problem is the x.

October 21st, 2012, 07:36 AM

G4143

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Join Date: Oct 2012

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No. The problem is the semi-colon at the end of the for statement which creates an empty block. Here what your for statement equals...

Code:

for(i=0;i<6;i++);

Which is the same as

Code:

for(i=0;i<6;i++){}/*Note the empty block*/

October 21st, 2012, 07:38 AM

Giorgos

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Join Date: Feb 2012

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Quote:

Originally Posted by G4143

No. The problem is the semi-colon at the end of the for statement which creates an empty block.

thank you very much!!!!!!

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