February 18th, 2013, 07:15 AM
I am new to operating system and i got some Questions about pipeling
Firstly ,the question we have A processor has 24 registers*, uses 8-bit immediate*, and has 36 different instructions* (corresponding to 36 operation codes**) in its instruction set.These 36 instructions are classified into 4 types as listed belowi just going to give out type c)
Type-C: takes 1 source register, 1 immediate, uses 1 destination register;
i know how to do this but the problem here is i don't know how many bit do 24 registers and 36 opcode require
(? = unknown)
i know the answer will be ?opcode+ ?registers + 8bits immediates + ?registers = bits
But i'd like to know how do i calculate the bits require
Secondly, there's question asking me how much the pipeline speedup ratio:
And this is all the information i get , but i don't know how many instruction in here also i don't know the Clock speed, how can i bring out the speed up ratio?
Assume a pipelined processor operates in four states: instruction fetch (IF), operand fetch (OF), operand execute (OE), and operand store (OS). A timing diagram of pipeline could be drawn as follows:
we have the following code with the data dependency.
ADD R1,R3,R2 [R1] ← [R3]+[R2]
SUB R4,R1,R5 [R4] ← [R1]-[R5]
MUL R6,R7,R8 [R6] ← [R7]*[R8]
This is the table :
Cycle 0 cycle 1 cycle 2 cycle 3 cycle 4 cycle 5 cycle 6 ......
ADD R1,R2,R3 IF OF OE OS
R1,R3,R2 IF OF OE OS
R4,R1,R5 IF OF OE OS
R6,R7,R8 IF OF OE OS
Many thanks for reply or view
my lecturer never reply my e-mail sigh...
February 26th, 2013, 06:11 PM
I think is correct I'm not too sure but this is what I have done. Basically if the register was 32 it would be 2^5 and if the instructions were 64 it would 2^6
so for c it would be:
6opcode+ 5registers + 8bits immediates + 5registers = 24bits/3bytes
If the numbers don't fit in base two exactly e.g 36 doesn't but
the closest to it is 2^5 we use that
Also if you get say 21bits you round it up to 24bits so its 3bytes bits should always be divided by 8.