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  #1  
Old June 17th, 2003, 05:08 PM
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Access Error

when I write a query, I get a couple of fileds with #Error because I attempted to divide by zero.

I want to write a query that finds fields with #Error and replaces them with a number.

I have tried the following and none have worked

select iif(x1 like '#Error', 99, x1)
select iif(x1 like "#Error", 99, x1)
select iif(x1 = '#Error', 99, x1)
select iif(x1 = "#Error", 99, x1)
select iif(x1 like '%#%', 99, x1)

any suggestions ??

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Old June 17th, 2003, 07:50 PM
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not completely sure, but i think #Error is not stored anywhere, it's just the indicator that access uses when you've made a booboo

why not use IIF logic to prevent the error? what does your query look like?

rudy

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Old June 18th, 2003, 01:56 AM
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hi r937,

the iff statement is the one that u provided me to calculate the average..

so something like

sum(iif(data1>-1 AND data1<11, data1, 0))/sum(iif(data1>-1 AND data1<11, 1,0))

but the problem here is in some cases, (depending on criteria I specify), if none of the values return true.. I get an error statement..

so in column A
A

99
33
44

since none of these values fall withing the range, the query will return an error as the average, "#Error"

what would be nice is if the #Error is encountered.. I would like it to be replaced with a numer like say 99

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Old June 18th, 2003, 06:43 AM
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you can nest them --
Code:
iif(
   sum( iif(data1>-1 AND data1<11,1,0) ) = 0
   , 99
   , sum(iif(data1>-1 AND data1<11, data1, 0))
    /sum(iif(data1>-1 AND data1<11, 1, 0))
   ) 

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Old June 18th, 2003, 10:12 AM
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thats awesome..
I tried it and it worked..

thanks a lot r937

Last edited by ecit12 : June 18th, 2003 at 12:07 PM.

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