Replace IDs with corresponding names

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April 27th, 2002, 10:56 AM

torkil

Another damn newb...

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Location: Bodø, Norway

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Replace IDs with corresponding names

I have a small tiny problem that I was hoping someone could help me with. Its Oracle... v8

I have a list of employees. Each employee belong to one workgroup, and each workgroup belong to one department. Each workgroup has got a workgroup leader (w_leader) and each department has got a department leader (d_leader). Both w_leader and d_leader are foreign keys that references EmployeeID. With me so far???

Now, I have 3 tables:

Code:

employee (employeeID, name, departmentID)
department (departmentID, name, d_leader)
workgroup (w_leader, employeeID)

With my select query I want to output:
ALL EMPLOYEES
with
- the name of the employee
- the name of the employees workgroup leader
- the name of the employees department leader

Now, with this query:

Code:

SELECT emp.name "EMPLOYEE", wgr.w_leader "WORKGROUP LEADER", dep.d_leader "DEPARTMENT LEADER" 
FROM emplyoees emp, workgroup wgr, department dep  
WHERE emp.employeeID = wgr.employeeID 
AND emp.departmentID = dep.departmentID;

I end out with this output:

Code:

EMPLOYEE   WORKGROUP LEADER   DEPARTMENT LEADER
------------------------------------------------
John    | 1 | 3
Alice   | 1 | 5
Mitch   | 2 | 5

Rather than this:

Code:

EMPLOYEE   WORKGROUP LEADER   DEPARTMENT LEADER
------------------------------------------------
John    | Peter   | Ralph
Alice   | Peter   | Sophie
Mitch   | Kirsten | Sophie

I don't manage to output the NAMES of the workgroup and department leaders, only their IDs. How can I get their names out on that list.... ?

__________________
Torkil Johnsen

Never underestimate the power of stupid people in large groups...
---------------------------(òÓ,)----

Last edited by torkil : April 27th, 2002 at 11:00 AM.

April 27th, 2002, 06:48 PM

Atrus

yet another member

Join Date: Feb 2001

Posts: 262

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Hi!

Well first of all: You knew that you were getting IDs only, right? You said it yourself:

Quote:

Both w_leader and d_leader are foreign keys that references EmployeeID

So you'll need additional joins to get the names for the IDs.

Code:

SELECT emp.name "EMPLOYEE", emp2.name "WORKGROUP LEADER", emp3.name "DEPARTMENT LEADER"
  FROM emplyoees emp, workgroup wgr, department dep, emplyoees emp2, emplyoees emp3
 WHERE emp.employeeID = wgr.employeeID
   AND emp.departmentID = dep.departmentID
   AND wgr.w_leader = emp2.employeeID
   AND dep.d_leader = emp3.employeeID;

I hope I didn't make any serious mistakes here. That query is untested :-)

Regards,

Atrus.

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April 29th, 2002, 02:16 AM

torkil

Another damn newb...

Join Date: Jan 2002

Location: Bodø, Norway

Posts: 94

Time spent in forums: < 1 sec
Reputation Power: 7

Ahhh....

Genious. Additional joins with additional table aliases. Brilliant

Yes I knew I was only going to get ID's.

April 29th, 2002, 09:02 AM

Atrus

yet another member

Join Date: Feb 2001

Posts: 262

Time spent in forums: < 1 sec
Reputation Power: 8

Hi!

"What an honour!" (Zoidberg)

Atrus.

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