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  #1  
Old June 23rd, 2003, 06:33 PM
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SQL Query 2

I have a table as such


Name A B
asdf h k
asdf h
asdf j k
asdf k h
jklm h k
jklm j k
jklm h j

what I want to do is this

get the total occurances of 'h' in field A and B and group by name

so my output would look like this

Name h k
asdf 3 3
jklm 2 2

hopefully this makes sense..

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  #2  
Old June 23rd, 2003, 09:07 PM
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this is just like your other question
Code:
select Name
     , sum(
    case when A='h' or B='h' then 1 else 0 end
          ) as h
     , sum(
    case when A='k' or B='k' then 1 else 0 end
          ) as k
  from yourtable
group
    by Name

rudy
http://r937.com/

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  #3  
Old June 24th, 2003, 12:17 PM
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thanks for ur response rudy

however it doesn't seem to work.

This is what I have

Code:
SELECT [Incident Reports].Program, SUM( CASE WHEN ([Incident Reports].[Code (a)] = 'AV') OR ( [Incident Reports].[Code (b)]='AV') THEN 1 ELSE 0 END) AS AV
FROM [Incident Reports]
WHERE ((([Incident Reports].[Date of Incident]) Between #1/1/2002# And #4/30/2003#))
GROUP BY [Incident Reports].Program;



it gives me the following error

Syntax error (missing operator) in query operation..

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Old June 24th, 2003, 12:32 PM
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hmm.. I think the solution u provided only works on MS SQL Server

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  #5  
Old June 24th, 2003, 05:22 PM
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the solution i gave is standard sql

you did not say what your database is, so if it doesn't support standard sql, that'd be your problem, no?

i shall make a guess that you're using microsoft access

try this --
Code:
select Program
     , sum( 
         iif([Code (a)]='AV',1,
         iif([Code (b)]='AV',1,0))
          ) as AV
  from [Incident Reports]
 where [Date of Incident]
       between #1/1/2002# And #4/30/2003#
group
    by Program

rudy

Last edited by r937 : June 24th, 2003 at 05:24 PM.

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  #6  
Old June 24th, 2003, 05:48 PM
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hey.. thanks..

thats what I did..
and it worked..

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