Algorythm Task

hello there,
as new in delphi and generally in porgramming, i want to create a list of swaping chars.
What do i mean....
All keyboard keys result to all possible combination!
A example will be very usefull so:
the choice of chars will be :
abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789!@#$%^&*();:'"/\}{[],.><
and the result for eight limit number like this:
8!QvSe:/
lY^Ne[(T
->7,agUo
l4};b]*P
&(#H!9Hs
>yj4l@NB
dm[i$w06
&O(d<*o8
n'2c{ib)
p-"V|4"/
S"tV0Fh-
99/&znG0
]2>sEs!9
NAE="9I2
<p%Zw!2h
2hboED^E
1EnL5FYx
yA);(1i<
m^[owOW2
dJ?#)'l*

or just like using a array ( i suppose its easier) to have a result like this:

00000000
00000001
00000002
00000003
....
0000000a
0000000b
....
0000000A
0000000B
...
0000000? <-- last box of arrow
....
00000010
00000011
etc..
11111110
11111111
11111112


Thank you for any suggestion, solution

Hard to be sure what you are looking for.

If you are looking to pick 8 characters at random from the full list then look up the random function.

Thank you for answering. Well i have done solutions with randomize char but it is not what i need.
My basic idea is to create a result of random string within a length, but i need to print it all the possible combination of selected string. If i use just random fuction i will not get 100% of combination. To do it i suppose i ll need an array to load strings and call them one by one as a stable until it finish all combination with full array. My first question is if i need as many array as my result lenght will be?

Sorry I do not understand what you are trying to achieve.