Check NRIC

how do i do a check to see if the user input of NRIC is in S1234567D format. 1st char has to be either S or F, then follow by 7 digits and last char has to be a alphabet from a to z.

Codes would be helpful. thanks.

pls help asap.

Easiest way is going to be regex.
[CODE]
import java.util.regex.*;

if ( Pattern.matches( "^[SF][0-9]{7}\p{Alpha}$", request.getParameter( "inputString" ) ) ) {
.. do code ..
} else {
.. no match ..
}

If you're going to be doing multiple matches you'll want to compile the pattern first. See http://java.sun.com/j2se/1.4/docs/a...ex/Pattern.html for instructions.

currently i am using the 1.3.1 api. it does not have regex. so what do i do??

upgrade

You're going to have to test properties on the string, then.
string.length() == 9
string.substring( 0, 1 ) == "S" || string.substring( 0, 1 ) == "F"
try {
Integer.parseInt( string.substring( 1, 9 ) );
} catch ( NumberFormatException nfe ) {
... these are not the numbers you are looking for, move along ...
}
string.substring( 8, 9 ).toUpperCase() > "A" && string.substring( 8, 9 ).toUpperCase() < "Z"

I'm not sure about that last one. You may need to convert it to a character or something first.

i have tried ur method.
there is smthing wrong with the middle 7 chars of the NRIC.

What i have now is:
it should check the nric is valid.
if it is valid, it prints "Ok".
however, now if the user types in "SdfgewgfW", as you can see the middle 7 chars are not integers. other than printing out "Middle 7 chars are not DIGITS", it prints out "Middle 7 chars are not DIGITS. Ok."

which means it also prints out the statement for valid nric.

Pls help asap...

i can't get it still..
and i have already done this, but the middle 7 chars check still doesn't work..

pls suggest..

Codes
___________________________________________


//check NRIC length = 9
if (nric.length()==9)
{
//check NRIC 1st char = uppercase "S" or "F"
if(nric.substring(0,1).equals("S") || nric.substring(0,1).equals("F"))
{
//check NRIC middle 7 chars are digits
try
{
Integer.parseInt(nric.substring(1,8));
}
catch ( NumberFormatException nfe )
{
out.println("Middle 7 chars are not DIGITS.");
}
//check NRIC last char = uppercase "A" to "Z"
if(nric.substring(8,9).equals("A") || nric.substring(8,9).equals("B") || nric.substring(8,9).equals("C") || nric.substring(8,9).equals("D") || nric.substring(8,9).equals("E") || nric.substring(8,9).equals("F") || nric.substring(8,9).equals("G") || nric.substring(8,9).equals("H") || nric.substring(8,9).equals("I") || nric.substring(8,9).equals("J") || nric.substring(8,9).equals("K") || nric.substring(8,9).equals("L") || nric.substring(8,9).equals("M") || nric.substring(8,9).equals("N") || nric.substring(8,9).equals("O") || nric.substring(8,9).equals("P") || nric.substring(8,9).equals("Q") || nric.substring(8,9).equals("R") || nric.substring(8,9).equals("S") || nric.substring(8,9).equals("T") || nric.substring(8,9).equals("U") || nric.substring(8,9).equals("V") || nric.substring(8,9).equals("W") || nric.substring(8,9).equals("X") || nric.substring(8,9).equals("Y") || nric.substring(8,9).equals("Z"))
{
out.println("Ok.");
}
else
{
out.println("NRIC last char should be a UPPERCASE ALPHABET.");
}
}
else
{
out.println("NRIC first char should be UPPERCASE S or F.");
}
}
else
{
out.println("NRIC total length not = 9.");
}
}

____________________________________________________

You're going to need to move the try/catch block so that it surrounds the whole thing. Otherwise, the exception is thrown, caught, and everything else just proceeds like normal.


try
{
//check NRIC length = 9
if (nric.length()==9)
{
//check NRIC 1st char = uppercase "S" or "F"
if(nric.substring(0,1).equals("S") || nric.substring(0,1).equals("F"))
{
//check NRIC middle 7 chars are digits
Integer.parseInt(nric.substring(1,8));
//check NRIC last char = uppercase "A" to "Z"
if(nric.substring(8,9).equals("A") || nric.substring(8,9).equals("B") || nric.substring(8,9).equals("C") || nric.substring(8,9).equals("D") || nric.substring(8,9).equals("E") || nric.substring(8,9).equals("F") || nric.substring(8,9).equals("G") || nric.substring(8,9).equals("H") || nric.substring(8,9).equals("I") || nric.substring(8,9).equals("J") || nric.substring(8,9).equals("K") || nric.substring(8,9).equals("L") || nric.substring(8,9).equals("M") || nric.substring(8,9).equals("N") || nric.substring(8,9).equals("O") || nric.substring(8,9).equals("P") || nric.substring(8,9).equals("Q") || nric.substring(8,9).equals("R") || nric.substring(8,9).equals("S") || nric.substring(8,9).equals("T") || nric.substring(8,9).equals("U") || nric.substring(8,9).equals("V") || nric.substring(8,9).equals("W") || nric.substring(8,9).equals("X") || nric.substring(8,9).equals("Y") || nric.substring(8,9).equals("Z"))
{
out.println("Ok.");
}
else
{
out.println("NRIC last char should be a UPPERCASE ALPHABET.");
}
}
else
{
out.println("NRIC first char should be UPPERCASE S or F.");
}
}
else
{
out.println("NRIC total length not = 9.");
}
}
}
catch ( NumberFormatException nfe )
{
out.println("Middle 7 chars are not DIGITS.");
}

thanks... it works..
i also need to ask if u know how to check a string to see if it contains salutations such as Mrs, Miss, Mdm, Mr; etc..

pls help if u know..

The String class has a startsWith() function.

what if the user enters the salutations at the end of the string or in the middle of the string?? is there smthing like a contain method, whereby it checks if the string contains certain word??

Yup. Bookmark this link. It's your friend.
http://java.sun.com/j2se/1.3/docs/api/
Get familiar with the javadoc, and you'll be able to answer 90% of your own questions.

As for the function you need:
http://java.sun.com/j2se/1.3/docs/a...ng.html#indexOf(java.lang.String)