Replace specific char in string with fillPolygon()

Ok, so I have limited coding experience and have only done basic stuff in VB

So basically i convert my string to char then loop through each char if a char is S i want it to display my own poly.

I think my problem is calling the method(?) to draw it. If i comment out the loop and just display the chars it works fine.

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edit:
I have figured it out, my poly was an invalid shape thus not displaying.

now after drawing a poly how do i "translate" (move it) in my applet window?

Can you explain what the problem is?

If letter is a char[], then you can test one of its elements directly using the == operator:
letter[i] == 'S'
and not have to convert it to a String.

The problem is that my polygon doesnt replace my "S" char.

basically

the user enters a word

i then add the word to a char array

i then use a loop to check each char in the array and display it exept when the char is "S" i want to display an "S" shaped poly using " fillPolygon(); ".

all my code for this so far is good exept displaying my own "S" shaped fillPolygon(); instead of the single char "S"


my code above takes each char and displays each one in a horizontal line exactly 20px away. my hope were that if my if statement sees and S it was draw my drawS polygon

Do you want to clear the graphics area before each time you draw?
Call the super.paint() method.

Where does the code change the location of where the polygon will be drawn?

I have figured it out, my poly was an invalid shape thus not displaying.

now after drawing a poly how do i "translate" (move it) in my applet window?

Change the x,y values that define its location.

Hey, how did you go about this issue?.. i have the same problem but for mine, i have drawn out the polygon, but instead of the letter being replaced, the polygon is drawn underneath the entered text.