Hi,
I´m sorry I had to get your attention that way (

), but I have a very urgent question:
I created a pop-up window Y from the main window X, and now I want to make it possible to select a link from a pull-down menu in Y - and the page should appear in X.
Right now I use this form:
<SCRIPT language="JavaScript">
<!--
function fenster()
{
opener.location.href = "../domain/"
}
//-->
</SCRIPT>
and this pull-down:
<select name=site SIZE=1 onChange="fenster(this.form)">
<option value="http://www.yoursite.com">Go to....
<option value="http://www.yahoo.com">Yahoo
<option value="http://www.metacrawler.com">Metacrawler
<option value="http://www.altavista.digital.com">Altavista
<option value="http://www.webcrawler.com">Webcrawler
<option value="http://www.lycos.com">Lycos
<option value="http://javascript.internet.com">JavaScript Source
</select>
</form>
but now I only get to ../domain, doesn´t matter what option I select.
Is it possible to modify this script to use for my purpose (right now it creates a pop-up, but it might help):
<SCRIPT LANGUAGE="JavaScript">
<!-- Begin
function formHandler(form) {
var windowprops = "height=500,width=500,location=no,"
+ "scrollbars=no,menubars=no,toolbars=no,resizable=yes";
var URL = form.site.options[form.site.selectedIndex].value;
popup = window.open(URL,"MenuPopup",windowprops);
}
// End -->
</script>
Could you please help me and tell me the code to use?
Thanks so much,
steve