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Updating hidden field with javascript for posting
Discuss Updating hidden field with javascript for posting in the JavaScript Development forum on Dev Shed. Updating hidden field with javascript for posting JavaScript Development forum discussing JavaScript and DHTML, AJAX, and issues such as coding cross-browser JavaScript.
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February 16th, 2013, 01:42 PM
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Registered User
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Join Date: Feb 2013
Posts: 5
Time spent in forums: 1 h 41 m 3 sec
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Updating hidden field with javascript for posting
Hi guys,
im trying to send hidden field value's using ajax so that I dont need to refresh the page. I do have this functionality working but one of my variables requires to be updated every time that I press the "next page" link (offset +15)
I found some javascript code which apparently should be able to achieve this. The javascript variable does update (itterates +15 on link click - verified by doing an alert(document.jax.offset.value) but the hidden field value does not pass the updated value when posted.
any idea's guys?
My hidden form code
Code:
echo '<form id="jax" name="jax" method="post">';
echo '<input type="hidden" id="player" value="'.$player.'"></input>';
echo '<input type="hidden" id="link" value="'.$link.'"></input>';
echo '<input type="hidden" id="genre" value="'.$genre.'"></input>';
echo '<input type="hidden" id="offset" name="offset" value="0"></input>';
echo '<a href="#" id="back" onclick="backpage()" >Back</a>';
echo '<a href="#" id="forward" onclick="addpage()">Forward</a><<br>';
echo '</form>';
javascript functions to add 15 & subract 15 to the offset hidden field ( back + add links)
Code:
<script type="text/javascript">
addpage = function(){ document.jax.offset.value = document.jax.offset.value*1 + 15 ;
return true;}
</script>
<script type="text/javascript">
backpage = function(){ document.jax.offset.value = document.jax.offset.value*1 - 15 ;
return true;}
</script>
my javascript file which passes the variables
Code:
jQuery(document).ready(function() {
var link = jQuery("#link").val();
var player = jQuery("#player").val();
var offset = jQuery("#offset").val();
jQuery("#forward").click(function(){
jQuery.ajax({
type: 'POST',
url: '/wordpress/wp-admin/admin-ajax.php',
data: {
action: 'sfunction',
link: link,
player: player,
offset: offset,
},
success: function(data, textStatus, XMLHttpRequest){
jQuery("#div").html('');
jQuery("#div").append(data);
},
error: function(MLHttpRequest, textStatus, errorThrown){
alert(errorThrown);
}
});
});
});
any idea's guys? as I said all the variables do pass over but the "offset" value is always passed over as "0" even though the local javascript variables does indeed increment when the "addpage" link is clicked
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February 16th, 2013, 09:56 PM
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Contributing User
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Try putting your input value variables inside the jQuery("#forward") function. It looks like those variables are just outside the scope of that function. I maybe wrong, but test it and see.
Code:
jQuery(document).ready(function() {
jQuery("#forward").click(function(){
var link = jQuery("#link").val();
var player = jQuery("#player").val();
var offset = jQuery("#offset").val();
// proceeding function below...
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February 17th, 2013, 11:25 AM
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Registered User
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Join Date: Feb 2013
Posts: 5
Time spent in forums: 1 h 41 m 3 sec
Reputation Power: 0
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do you mean like this?
Code:
<script type="text/javascript">
var offset = jQuery("#offset").val();
addpage = function(){ document.jax.offset.value = document.jax.offset.value*1 + 15 ;
return true;}
</script>
<script type="text/javascript">
var offset = jQuery("#offset").val();
backpage = function(){ document.jax.offset.value = document.jax.offset.value*1 - 15 ;
return true;}
</script>
I tried that and it never worked
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February 17th, 2013, 09:24 PM
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Contributing User
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Quote: | Originally Posted by scottish_jason do you mean like this?
Code:
<script type="text/javascript">
var offset = jQuery("#offset").val();
addpage = function(){ document.jax.offset.value = document.jax.offset.value*1 + 15 ;
return true;}
</script>
<script type="text/javascript">
var offset = jQuery("#offset").val();
backpage = function(){ document.jax.offset.value = document.jax.offset.value*1 - 15 ;
return true;}
</script>
I tried that and it never worked |
Uhhh... no; like this:
Code:
jQuery(document).ready(function() {
jQuery("#forward").click(function(){
var link = jQuery("#link").val();
var player = jQuery("#player").val();
var offset = jQuery("#offset").val();
jQuery.ajax({
type: 'POST',
url: '/wordpress/wp-admin/admin-ajax.php',
data: {
action: 'sfunction',
link: link,
player: player,
offset: offset,
},
success: function(data, textStatus, XMLHttpRequest){
jQuery("#div").html('');
jQuery("#div").append(data);
},
error: function(MLHttpRequest, textStatus, errorThrown){
alert(errorThrown);
}
});
});
});
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February 17th, 2013, 10:10 PM
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Registered User
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Join Date: Feb 2013
Posts: 5
Time spent in forums: 1 h 41 m 3 sec
Reputation Power: 0
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Quote: | Originally Posted by web_loone08 Uhhh... no; like this:
Code:
jQuery(document).ready(function() {
jQuery("#forward").click(function(){
var link = jQuery("#link").val();
var player = jQuery("#player").val();
var offset = jQuery("#offset").val();
jQuery.ajax({
type: 'POST',
url: '/wordpress/wp-admin/admin-ajax.php',
data: {
action: 'sfunction',
link: link,
player: player,
offset: offset,
},
success: function(data, textStatus, XMLHttpRequest){
jQuery("#div").html('');
jQuery("#div").append(data);
},
error: function(MLHttpRequest, textStatus, errorThrown){
alert(errorThrown);
}
});
});
});
|
thanks for the help, but unfortunately that never worked. As i was saying, all of the values pass over fine, its just that the updated value (from the addpage/backpage function) does not pass over even though the local javascript variable does indeed update.
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February 18th, 2013, 12:14 AM
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Registered User
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Join Date: Feb 2013
Posts: 5
Time spent in forums: 1 h 41 m 3 sec
Reputation Power: 0
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Quote: | Originally Posted by scottish_jason thanks for the help, but unfortunately that never worked. As i was saying, all of the values pass over fine, its just that the updated value (from the addpage/backpage function) does not pass over even though the local javascript variable does indeed update. |
sorry never mind, I got it
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