[Bash] Help with include array value in unix command

Dev Shed Forums Sponsor:

September 16th, 2011, 11:01 AM

akaballa123

Registered User

Join Date: Sep 2011

Posts: 23

Time spent in forums: 5 h 5 m 10 sec
Reputation Power: 0

[Bash] Help with include array value in unix command

Hi there, I have created an array in which I store multiple names. I thne run a for loop to iterate through 2 names in the array. I then run another script and input the current name as an argument to that script. my problem is that during the first iteration, the script works fine, but during the second iteration, the second name does not get passed to the script, but the first one gets passed again.

say I have two inputs: apples, oranges stored in jBPMarray.

in for loop:

in first iteration: i want to run

Code:


/usr/local/report.sh apples

in second report I want to run:

Code:


/usr/local/report.sh oranges

instead the argument apples get used twice.

here is my code. I think there is something wrong with my syntax inside the for loop

Code:


#!/usr/bin/bash


jBPMarray=("$@")

echo -n "Specify number of reports to generate per hour : "
read num_reports_per_hr

echo -n "Specify a timestamp e.g. ( 01/01/2011 ) : "
read time_stamp;

output_dir=""
rpt_file_name=""
process_itr=${#jBPMarray[@]} 
echo "process_itr: "
echo $process_itr
index_itr=0

while [ "$process_itr" -ne 0 ]
do
    echo "current iteration: ${process_itr}"
    for ((j=0;j<=($num_reports_per_hr - 1);j++))
    do 
      echo "current number: "
      echo $j
      "/usr/local/report.sh" "$jBPMarray["$j"+"$index_itr"]"
      echo "Current Process:" 
      echo ${jBPMarray[$j]} 
      process_itr=$(($process_itr - 1));
      echo "process_itr: "
      echo $process_itr
      if [ "$process_itr" -eq 0 ]
      then 
            break;
      fi
      
    done
    
    echo "Sleeping"
    sleep 10
    index_itr="$index_itr"+"$num_reports_per_hr"

done

Any advise would be well appreciated. Plz Help! Thanks!!!

September 16th, 2011, 11:02 PM

SimonJM

Contributing User

Join Date: Mar 2006

Posts: 2,108

Time spent in forums: 1 Month 1 Week 1 Day 4 h 41 m
Reputation Power: 1485

You seem to be over-complicating things ...
Try (untested!):

Code:

#!/usr/bin/bash

echo -n "Specify number of reports to generate per hour : "
read num_reports_per_hr

echo -n "Specify a timestamp e.g. ( 01/01/2011 ) : "
read time_stamp;

output_dir=""
rpt_file_name=""
index_itr=0

for process_itr in $*
do
    echo "current iteration: ${process_itr}"
    for ((j=0;j<=($num_reports_per_hr - 1);j++))
    do 
      echo "current number: "
      echo $j
      /usr/local/report.sh "${process_itr}"
      echo "Current Process:" 
    done
    echo "Sleeping"
    sleep 10
done

__________________
The moon on the one hand, the dawn on the other:
The moon is my sister, the dawn is my brother.
The moon on my left and the dawn on my right.
My brother, good morning: my sister, good night.
-- Hilaire Belloc

Last edited by SimonJM : September 18th, 2011 at 07:05 AM. Reason: Remove quotes from around $*

September 19th, 2011, 08:48 AM

akaballa123

Registered User

Join Date: Sep 2011

Posts: 23

Time spent in forums: 5 h 5 m 10 sec
Reputation Power: 0

Quote:

Originally Posted by SimonJM

You seem to be over-complicating things ...
Try (untested!):

Code:

#!/usr/bin/bash

echo -n "Specify number of reports to generate per hour : "
read num_reports_per_hr

echo -n "Specify a timestamp e.g. ( 01/01/2011 ) : "
read time_stamp;

output_dir=""
rpt_file_name=""
index_itr=0

for process_itr in $*
do
    echo "current iteration: ${process_itr}"
    for ((j=0;j<=($num_reports_per_hr - 1);j++))
    do 
      echo "current number: "
      echo $j
      /usr/local/report.sh "${process_itr}"
      echo "Current Process:" 
    done
    echo "Sleeping"
    sleep 10
done

Oh yea i realized how complicated my code was. I made the necessary changes thanks to you help!

.

I am have some trouble with a regex mattern matching then string removal.

Basically i have a variable with the following string:

Code:


 rpt_file="mucm_turnover-survey_${LAST_BUS_DAY}.csv< FeedName>"

I would like to remove the substring < FeedName>.

I did some research and found out that the best way to remove a part of your string is to use the following syntax: ${string#substring}.

I tried incorporating that syntax, but am failing continuously in removing the substring. I am not sure if there is something wrong with my pattern or the syntax or both ( yikes!). here is my code:

Code:


read ADDR1 ADDR2 ADDR3 ADDR4 <<<$(IFS="\/"; echo $output_dir)
    rpt_file="$ADDR4"  # stores the string "mucm_turnover-survey_${LAST_BUS_DAY}.csv< FeedName>" 
    rpt_file=${rpt_file#<.*>}

    echo "report file name: "
    echo $rpt_file

Plz help!!

September 19th, 2011, 11:02 AM

SimonJM

Contributing User

Join Date: Mar 2006

Posts: 2,108

Time spent in forums: 1 Month 1 Week 1 Day 4 h 41 m
Reputation Power: 1485

Try:

Code:

rpt_file=${rpt_file%<*>}

September 19th, 2011, 12:29 PM

akaballa123

Registered User

Join Date: Sep 2011

Posts: 23

Time spent in forums: 5 h 5 m 10 sec
Reputation Power: 0

Quote:

Originally Posted by SimonJM

Try:

Code:

rpt_file=${rpt_file%<*>}

Oh wow it worked!! So simple yet effective. Didnt realize it would make a difference to start from back of the string as opposed to starting from the front.

September 19th, 2011, 05:03 PM

SimonJM

Contributing User

Join Date: Mar 2006

Posts: 2,108

Time spent in forums: 1 Month 1 Week 1 Day 4 h 41 m
Reputation Power: 1485

Quote:

Originally Posted by akaballa123

Oh wow it worked!!

Less surprise please!!!

[Bash] Help with include array value in unix command

Developer Shed Advertisers and Affiliates