Calling another shell script with relative path problem

Hello,

I want to execute a file (runFile.sh) from a different directory.
Inside 'runFile.sh' (which is not my code so I can't change this file) first few lines are like this:



So, when I try to call this file it is failing saying that 'env.sh' not found.
My Code:


Then I changed code like this.



When I run this file the cd command doesn't work.

How can I solve this problem?

This usually isn't a problem when you just use absolute paths to rather than using cd to change directories.

How are you executing this? through crontab?

I tried using full path to execute the script.
But inside that script it's doing cd and trying to load a file.
I am running my script from ksh shell manually (no corntab I guess).

If you see my original post, I had posted my first code and the second code.
Error messages:

1. First Code:
env.sh: cannot open [No such file or directory]

2. Second Code:
runFile.sh: not found [No such file or directory]

add an echo $FOLDER_ID to your script to see if your variable is getting screwed up somehow...

Also why do you have two variables for BASE_LOC and BASE_SOURCE_LOC?

Couldn't you simply do

BASE_LOC=/home/base/app/peter/source/patch/$FOLDER_ID ?

set that then do an echo $BASE_LOC
/bin/ls -l $BASE_LOC

does that work?

Thanks "safesurfdns" for helping me out.

Let me explain you the scenario here.

I have two separate types of scripts here.
1. You can say third party script in a separate location. I can't change their scripts nor the location ie. BASE_SOURCE_LOC.
2. My own script which is calling #1 and in another location. ie. BASE_LOC

Running #1 using direct path will never work as inside their code they are using relative path.
First couple of lines of their code:


So, I somehow have to change to their location (BASE_SOURCE_LOC) to execute their script(#1) from my script (#2).

Please let me know if you need more info.

resolved the problem by implementing pushd and popd functions.
thanks guys...