Exec command with grep output

Hello,

I have a requirement to find the files having its name as ack_reply. However, there are many other files in the same directory as these resides. Now I have to remove these files from the folder and retain others after 7 days. So I tried to write the below script with grep command.

find $directory -type f -mtime +7 | grep ack_reply

Please let me know how can I pass this output to -exec command.

If I am not using grep command my script would be as

find $directory -type f -mtime +7 -exec remove.sh {}\\;;

How can I use -exec with grep and find. Please let me know

Rather than using 'grep', you can use the -name option to 'find', i.e.:

But we can use -name when the file name is with ack_reply. My requirement is to identify all the files that have filenames as ack_reply some where in between. I mean the ack_reply is part of a file name

In that case:

Thanks..this helped me a lot