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  #1  
Old April 27th, 2008, 09:18 PM
kim187 kim187 is offline
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ison script please look at

my friend has challenged me does anyone have any input

# Determine if someone is logged on
# Version 4.0
if [ “$#” ne
1 ]
then
echo “ Incorrect number of arguments”
echo “Usage: $ ison4 <user>”
else
user=“$1”
if who | grep “$user” > /dev/null
then
echo “$user is logged on”
else
echo “$user is not logged on”
fi
fi


shell program named ison that will check every 5 seconds whether a particular user has
logged into the system. When the user logs in, print a message on your terminal flagging the login.
(Make sure the user entered is a valid user.) (hint use ison5

Last edited by kim187 : May 1st, 2008 at 01:06 AM. Reason: vhange

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Old April 28th, 2008, 02:55 PM
LKBrwn_DBA LKBrwn_DBA is offline
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Talking


It's a start, at least you got the first line correct...

Here are some hints ( enclosed in [] ):

Quote:
Write a shell program named ison that will check every 5 seconds [crontab] whether a particular user has
logged into the system [who|grep]. When the user logs in, print a message on your terminal flagging the login [send].
The rest seems to be some "manual" verification.

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Last edited by LKBrwn_DBA : April 28th, 2008 at 03:03 PM.

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Old April 29th, 2008, 02:34 AM
SimonJM SimonJM is offline
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cron has a minimum 'resolution' of 1 minute, so you'd need a loop with a sleep 5 to get close to 5 second gaps between checks.
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