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  #1  
Old February 9th, 2001, 07:27 AM
olekb olekb is offline
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Question

I need some help with a php script. I'm trying to send a variable to another php file within the wml-url :

if(mysql_num_rows($fagTabell) > 0)
{
while($row=mysql_fetch_array($fagTabell))

print "<a href=\"dato.php?fagkode=" . row["fagkode"] . "\">" . $row["fagbeskrivelse"] . "</a><br/>";

}//while
}//if

These lines creates wml-urls, where "row["fagkode"] is to be sent with the url..It seems like I have managed to send it, but I can't use the variable in dato.php...

I've tried this in dato.php :

$kode=HTTP_GET_VARS["fagkode"];
echo"<p>$kode</p>";

(wich only creates the error "Unsupported content-type: text/html")

or just :

print"$fagkode";
doesn't print anything at all).

Could use some help here!

Ole Kristian
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  #2  
Old February 20th, 2001, 10:59 PM
sharky121 sharky121 is offline
...try and try again
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Hi Ole,

From the code you supplied it looks like you're missing a curly bracket:

while($row=mysql_fetch_array($fagTabell)) { <- This one

Hope this clears up your problem.

Ben

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Old February 26th, 2001, 08:05 PM
vsantola vsantola is offline
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Try this, instead:

if(mysql_num_rows($fagTabell) > 0)
{
while($row=mysql_fetch_array($fagTabell))

print "<a href=\"dato.php?fagkode=$row["fagkode"]\">$row["fagbeskrivelse"]</a><br/>";

}//while
}//if

(you have type row["fagkode"] instead of $row["faqkode"], and you can embebed your php variables in strings)...

Ah! don't forget to print the wml header, when you are writing WAP applications, before print something, just put this in your code:

print("Content-type: text/vnd.wap.wml\r\n\r\n");

this is the standard wap.wml header and will tell that your file is using this protocol...

Happy WAPPy...

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