February 8th, 2006, 07:18 AM
Regular Expression for Whole Words
I am try to build a query which only matches whole words and so far I've got this.
This will return rows which contain the string 'blah' without any numeric or alphanumeric characters beside it. However it doesn't return the rows where 'blah' is either at the start or end of the string as it expects any character except a-zA-Z0-0.
WHERE CorrectSpelling LIKE '%[^a-zA-Z0-9]blah[^a-zA-Z0-9]%'
Is there any way to accept string when there is nothing on either side as well?
February 8th, 2006, 08:22 AM
It really doesn't look as though only LIKE would support your situation. I don't see a way to optionally check for a pattern match - especially if it's at the beginning of a string. Regex would be the way to go.
One solution, combining LIKE with other methods, would be to just get the charindex of 'blah'. If it's greater than 0, check if the character before it is LIKE [^a-zA-Z0-9]
and if the position of 'blah' is less than (the len of the column - len of 'blah'), then check the character right after it it is LIKE [^a-zA-Z0-9]