the most recent address from each user by date

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June 8th, 2004, 07:44 AM

asmo

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Join Date: Jun 2004

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the most recent address from each user by date

Alright here's a table I have:

Id Effective Addy
1 10/10/2003 123 Test Lane
1 12/10/2003 No Exist Court
1 1/5/2004 Here I am!
2 6/6/2003 Some place
3 12/25/2003 Old place
3 1/30/2004 Now Place

I want to take the most recent address from each user by date- basically, I want this returned:

Id Addy
1 Here I am!
2 Some place
3 Now Place.

So I want each user's 'current' address. Is there a way in SQL to do this?

EDIT: I kind of changed my question, I just want the Id and the current Addy.

Can anyone give me a hand? Thanks a lot!

June 8th, 2004, 07:57 AM

asmo

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Join Date: Jun 2004

Posts: 22

Time spent in forums: < 1 sec
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Okay- here's where I'm at:

SELECT test.Id, FIRST(test.Addy) AS CurrAddy
FROM test
GROUP BY test.Id, test.Effect
ORDER BY test.Id,test.Effect DESC;

That gives me:

Id CurrAddy
1 Here I am!
1 No Exist Court
1 123 Test Lane
2 Some place
3 Now Place
3 Old place

That's almost what I want, now I just need the top 1 of each Id number. Any suggestions?

June 8th, 2004, 08:43 PM

brightlight

Contributing User

Join Date: Apr 2004

Posts: 371

Time spent in forums: 19 h 32 m 27 sec
Reputation Power: 5

Hi,

Following is the MS SQL Query. Change the table name and the column names accordingly

Quote:

SELECT *
FROM tb1 a
WHERE (Effective =
(SELECT MAX(effective)
FROM tb1 b
WHERE a.id = b.id))
ORDER BY id

__________________
Regards,

Brightlight

June 9th, 2004, 01:16 AM

Username=NULL

Contributing User

Join Date: Apr 2004

Location: TX

Posts: 249

Time spent in forums: 1 Day 7 h 6 m 42 sec
Reputation Power: 5

This could also work...

Code:

select	ID, Addy
from	Table 1 T1
join	(
	 select	ID, max(Effective) as maxEffective
	 from	Table1 T
	 group	by ID
	) as A
  on	T1.ID = A.ID and T1.Effective = A.maxEffective

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