
March 24th, 2000, 03:34 PM
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Junior Member
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Join Date: Mar 2000
Posts: 24
Time spent in forums: < 1 sec
Reputation Power: 0
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I'm working on a similar project at Martijn,
select distinct(owner), pet
from pet
group by pet; //
Could some one please help me with printing out the results.
Thanks in advance.
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