MySQL Help
 
Forums: » Register « |  User CP |  Games |  Calendar |  Members |  FAQs |  Sitemap |  Support | 
User Name:
Password:
Remember me
Go Back   Dev Shed ForumsDatabasesMySQL Help

Reply
Add This Thread To:
  Del.icio.us   Digg   Google   Spurl   Blink   Furl   Simpy   Y! MyWeb 
Thread Tools Search this Thread Rate Thread Display Modes
 
Unread Dev Shed Forums Sponsor:
  #1  
Old June 14th, 2000, 12:49 PM
kpmd kpmd is offline
Junior Member
Dev Shed Newbie (0 - 499 posts)
 
Join Date: Jun 2000
Posts: 3 kpmd User rank is Just a Lowly Private (1 - 20 Reputation Level) 
Time spent in forums: < 1 sec
Reputation Power: 0
There seem to be alot of ways to perform date subtraction but one way that I do not see in the documentation or posts is this:

I have a date in the future (TIMESTAMP1). I want to find out how many days,hours,minutes,seconds between NOW() and TIMESTAMP1.

All of the functions I have seen deal with either the difference in seconds, or formating a new date from the calculation. I am trying to get "countdown" information I guess you could call it, that says "x days, y hours, z minutes until TIMESTAMP.

If I have missed something obvious, my apologies, but any help would be greatly appreciated.

Thanks,
kp



Reply With Quote
  #2  
Old June 14th, 2000, 03:29 PM
rod k rod k is offline
Apprentice Deity
Dev Shed Loyal (3000 - 3499 posts)
 
Join Date: Jul 1999
Location: Niagara Falls (On the wrong side of the gorge)
Posts: 3,237 rod k User rank is Private First Class (20 - 50 Reputation Level)rod k User rank is Private First Class (20 - 50 Reputation Level) 
Time spent in forums: 4 m 8 sec
Reputation Power: 13
Send a message via AIM to rod k
The best idea I could come up with is to convert to a unix timestamp to get a difference in seconds. You would have to convert to ddhhmmss format from that.

select unix_timestamp(date_field)-unix_timestamp() as sec_diff from table;

Reply With Quote
  #3  
Old June 16th, 2000, 11:01 AM
kpmd kpmd is offline
Junior Member
Dev Shed Newbie (0 - 499 posts)
 
Join Date: Jun 2000
Posts: 3 kpmd User rank is Just a Lowly Private (1 - 20 Reputation Level) 
Time spent in forums: < 1 sec
Reputation Power: 0
Okay, that is something that I had considered but what is the best way to do the conversion to d:m:h:s afterwards?

Reply With Quote
  #4  
Old June 16th, 2000, 11:32 AM
rod k rod k is offline
Apprentice Deity
Dev Shed Loyal (3000 - 3499 posts)
 
Join Date: Jul 1999
Location: Niagara Falls (On the wrong side of the gorge)
Posts: 3,237 rod k User rank is Private First Class (20 - 50 Reputation Level)rod k User rank is Private First Class (20 - 50 Reputation Level) 
Time spent in forums: 4 m 8 sec
Reputation Power: 13
Send a message via AIM to rod k
$days=intval($timediff/86400);
$remain=$timediff%86400;
$hours=intval($remain/3600);
$remain=$remain%3600;
$mins=intval($remain/60);
$secs=$remain%60;

print "$days:$hours:$mins:$secs";

Reply With Quote
Reply

Viewing: Dev Shed ForumsDatabasesMySQL Help > computing d:h:m:s difference between two dates


Thread Tools  Search this Thread 
Search this Thread:

Advanced Search
Display Modes  Rate This Thread 
Rate This Thread:


Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

vB code is On
Smilies are On
[IMG] code is On
HTML code is Off
View Your Warnings | New Posts | Latest News | Latest Threads | Shoutbox
Forum Jump


Forums: » Register « |  User CP |  Games |  Calendar |  Members |  FAQs |  Sitemap |  Support | 
  
 





© 2003-2008 by Developer Shed. All rights reserved. DS Cluster 1 hosted by Hostway
Stay green...Green IT