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Help with "COUNT" :(

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  #1  
Old February 2nd, 2012, 01:01 PM
Shanks8124 Shanks8124 is offline
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Help with "COUNT" :(
Alright, so I have a few fields.

type, pokemon, gender

I want to be able to retrieve the exact amount of "male" pokemon in the game, exact amount of "female" Pokemon in the game, exact amount of "Genderless" Pokemon in the game, and the exact amount of "(?) Pokemon in the game. I want to display the results in a table.

Now all these symbols are in the "gender" field. I also want to group everything by the amount of Pokemon in gaming, using ASC to display the rarest one first.

I got a bit of it to work, but I want the "type" field to be incorporated with the "Pokemon" field.

For example, if I have data like this:

Type | Pokemon | Gender
Shiny Squirtle (?)
Shiny Squirtle (?)
Squirtle M
Squirtle F

I want the query to return this:

Pokemon | M | F | G | (?) | Total
ShinySquirtle 0 0 0 2 2
Squirtle 1 1 0 0 2

Would this be possible? I have tried it, but I cannot get it to work. I just need a simple query, but I also want to differentiate between different "types" of a Pokemon.

Thanks in advance.
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  #2  
Old February 2nd, 2012, 01:19 PM
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Quote:
Originally Posted by Shanks8124
Would this be possible?
yes, but why bother?

i mean, don't you have some application language here, like php?

that's where cosmetic re-arrangement of query results should take place
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  #3  
Old February 2nd, 2012, 02:03 PM
Shanks8124 Shanks8124 is offline
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Quote:
Originally Posted by r937
yes, but why bother?

i mean, don't you have some application language here, like php?

that's where cosmetic re-arrangement of query results should take place

Yes, I am using PHP, and I've tried echo'ing out the results, but I can't seem to get what I want.
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  #4  
Old February 3rd, 2012, 04:20 AM
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Yes, just grab the desired result set and handle the arithmetic at the application level (i.e., PHP)

If you really must do this in MySQL you can do something like the following. Be advised that, as written, this solution deviates from standard SQL:

Code:
DROP TABLE IF EXISTS pokemon;
CREATE TABLE pokemon
(id INT NOT NULL AUTO_INCREMENT PRIMARY KEY
,Pokemon VARCHAR(20)
,Gender VARCHAR(12)
);

INSERT INTO pokemon VALUES
(1,'Shiny Squirtle','(?)'),
(2,'Shiny Squirtle','(?)'),
(3,'Squirtle','M'),
(4,'Squirtle','F');

SELECT pokemon 
     , SUM(gender = 'M') M
     , SUM(gender = 'F') F
     , SUM(gender = '(?)') `(?)`
     , COUNT(*) Total  
  FROM pokemon 
 GROUP 
    BY pokemon;
+----------------+------+------+------+-------+
| pokemon        | M    | F    | (?)  | Total |
+----------------+------+------+------+-------+
| Shiny Squirtle |    0 |    0 |    2 |     2 |
| Squirtle       |    1 |    1 |    0 |     2 |
+----------------+------+------+------+-------+
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  #5  
Old February 3rd, 2012, 04:59 AM
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Quote:
Originally Posted by cafelatte
Be advised that, as written, this solution deviates from standard SQL:

here's a standard SQL version...
Code:
SELECT pokemon 
     , SUM( CASE WHEN gender = 'M' 
                 THEN 1 ELSE 0 END ) M
     , SUM( CASE WHEN gender = 'F' 
                 THEN 1 ELSE 0 END ) F
     , SUM( CASE WHEN gender = '(?)' 
                 THEN 1 ELSE 0 END ) "(?)"
     , COUNT(*) Total  
  FROM pokemon 
 GROUP 
    BY pokemon;
Last edited by r937 : February 3rd, 2012 at 05:04 AM.
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  #6  
Old February 3rd, 2012, 03:31 PM
Shanks8124 Shanks8124 is offline
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thanks for your help guys, but apparently the "type" and "Pokemon" are in 2 separate fields.

So 'ShinySquirtle' would not be in one field, it would be in 2 separate fields, as 'Shiny' is the Pokemon's 'type,' and 'Squirtle' is the Pokemon 'name.'

Any idea how I could group those together as well?

Is this what I should be doing?

Code:
$result=mysql_query("SELECT pokemon, SUM(CASE WHEN gender = 'â™' THEN 1 ELSE 0 END), SUM(CASE WHEN gender = '♀' THEN 1 ELSE 0 END), SUM(CASE WHEN gender = '(?)' THEN 1 ELSE 0 END), COUNT(*) Total FROM pokemon2 GROUP BY pokemon"); 
while($row = mysql_fetch_array( $result )) {

$type=$row['type'];
$pokemon=$row['pokemon'];
$genderM=$row['SUM(CASE WHEN gender = 'â™' THEN 1 ELSE 0 END)'];
$genderF=$row['SUM(CASE WHEN gender = '♀' THEN 1 ELSE 0 END)'];
$genderquestion=$row['SUM(CASE WHEN gender = '(?)' THEN 1 ELSE 0 END)'];


echo $type.$pokemon. " " .$genderM. " " .$genderF. " " .$genderquestion;

}
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  #7  
Old February 3rd, 2012, 05:40 PM
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Quote:
Originally Posted by Shanks8124
Is this what I should be doing?
i'm pretty sure the answer is no

but then, i don't do php and this isn't the php forum

the query you should be running is this one --
Code:
SELECT pokemon 
     , SUM( CASE WHEN gender = 'M' 
                 THEN 1 ELSE 0 END ) M
     , SUM( CASE WHEN gender = 'F' 
                 THEN 1 ELSE 0 END ) F
     , SUM( CASE WHEN gender = '(?)' 
                 THEN 1 ELSE 0 END ) "(?)"
     , COUNT(*) Total  
  FROM pokemon 
 GROUP 
    BY pokemon;
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  #8  
Old February 4th, 2012, 03:13 AM
cafelatte cafelatte is offline
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See how I provided CREATE and INSERT statements? If you think mine are wrong you're welcome to provide some of your own.
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Old February 5th, 2012, 02:26 PM
Shanks8124 Shanks8124 is offline
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Quote:
Originally Posted by cafelatte
See how I provided CREATE and INSERT statements? If you think mine are wrong you're welcome to provide some of your own.


Code:
INSERT INTO pokemon2 (user_id, pokemon_id, dex, type, pokemon, gender, level, experience, item attached, roster) VALUES ('1', '', 'Shiny', 'Squirtle', 'M', '', '125', NULL, '0');


This is how it would be set up in my database.
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  #10  
Old February 5th, 2012, 03:02 PM
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Quote:
Originally Posted by Shanks8124
This is how it would be set up in my database.
sorry, i don't buy that

that statement has at least two syntax errors

what happened when you tested the query i gave you?
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  #11  
Old February 5th, 2012, 03:17 PM
Shanks8124 Shanks8124 is offline
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Your Query works perfectly fine, but I also need to take the 'type' field into account. Other than that, it works brilliantly.

This would just be to show users how many Pokemon there are in game.
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  #12  
Old February 5th, 2012, 03:28 PM
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Quote:
Originally Posted by Shanks8124
...I also need to take the 'type' field into account.
so, add it to both the SELECT clause and the GROUP BY clause
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  #13  
Old February 5th, 2012, 03:33 PM
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Quote:
Originally Posted by r937
so, add it to both the SELECT clause and the GROUP BY clause


Wow, thanks a bunch. That worked out really well.
Now I just need to find out how I can echo the results out.
Thanks again, you two.

edit: I got it to work with PHP, thanks again!
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  #14  
Old February 5th, 2012, 04:47 PM
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'thanks a bunch'

Well that's gratitude for you!!!
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