what about checkboxes and mysql?

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July 12th, 2000, 07:57 PM

ph0123

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This question is similar to one posted previously by icewind0. That person asked about storing responses from a select element on a form. The response to that was to create a table with the limited responses, etc. What about check boxes? I would imagine you could create a table to store all the possible answers, but how would you associate a variable number of answers with the user who answered them? For example, on a form that says: check all the sports you like, there could be 12 sports listed. Each user who fills out the form could pick 0, 1, or up to 12. If you have a table with the users data in it, what is the right/best way to store this type of input?

Thanks for any help.

July 13th, 2000, 06:03 AM

releasedj

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Create a table in your db called sports for example:

CREATE TABLE sports (
like SET('football', 'tennis','rugby')
);

This field will now only take these three sporting values.

Next here's some code to input into the table

********************* HTML ******************

<?
print "<HTML>n";
print "<HEAD>n";
print "</HEAD>n";

print "<BODY>n";
print("Choose a sport that you like<BR>n");

print("<FORM ACTION="sportphp.php3">n");

print("<INPUT TYPE="checkbox" NAME="sport[]" VALUE="football">Football");

print("<INPUT TYPE="checkbox" NAME="sport[]" VALUE="tennis">Tennis");

print("<INPUT TYPE="checkbox" NAME="sport[]" VALUE="rugby">Rugby");

print("<INPUT TYPE="submit">n");
print("</FORM>n");
print("</BODY>n");
print("</HTML>n");
?>

On submit this will create an array '$sport[]' with the values of the 3 sports.

****************** php ********************

<?
if(isset($sports))
{
$mylink = mysql_connect('localhost','user','password');

$query = "INSERT INTO sports(like) VALUES('$sports[0]','$sports[1]','$sports[2]')";

$result = mysql_db_query('dbname',$query, $mylink) or die("Could not execute query");
}
else
{
print("No items were selected!");
}
?>

This should work although I just typed it now and haven't checked it for errors.

Kelvin

July 13th, 2000, 04:30 PM

ph0123

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Thanks for the comprehensive reply, but that doesn't work. I get an error that says column count does not equal value count when I try the insert. Is it necessary to build a comma separated list of the values then insert that?

Thanks.

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