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  #1  
Old March 3rd, 2004, 06:01 PM
adiwood adiwood is offline
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Smile Subnetting

in my example i have the ip address 200.200.200.0 and i need three subnets. Im a little unsure on how to do this and have only managed to get 4 subnets, what do i do?

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  #2  
Old March 3rd, 2004, 06:34 PM
tawi tawi is offline
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numbers of subnets go like this
1
2
4
8
16
32
64
128
256

in other words you can't.

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Old March 4th, 2004, 06:27 AM
juniperr juniperr is offline
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if you where given an IP address of 200.200.200.0/24 then you would break it down into subnets by barrowing bits from the last octet. lets say you barrow 3 bits which would give you a /27 mask the way to figure how many subnets there would be is ( 2 to the 3rd power) -2) or 8-2=6 unless using VLSM. the number of hosts then would be (2 to the 5th power) -2) because there are 5 host bits left after barrowing 3 for the subnet. so with three bits barrowed you have enough to do the 3 subnets with 3 left over for expansion. If you are asking if you could get exactly 3 subnets then look at the post above mine and dont look at the 9th bit of 256 hehe

Last edited by juniperr : March 4th, 2004 at 07:23 AM.

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Old March 4th, 2004, 07:06 AM
adiwood adiwood is offline
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Talking

in was right all along!!

Thanx for the help

Adi

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Old March 4th, 2004, 07:19 AM
juniperr juniperr is offline
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well almost if you are using a cisco router then you could barrow only 2 bits and enable ip subnet zero which would give you 3 usable subnets exactly. This however could pose a problem if you are hosting an older Unix box.

formula...
[ = 2^(mask bits) -2 ] and hosts/subnet [ = 2^(32 -16 -mask bits) -2 for class B]. The +1 in front of subnets should be added if ip subnet-zero command is used on Cisco router

Last edited by juniperr : March 4th, 2004 at 07:21 AM.

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