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  #1  
Old November 17th, 2009, 06:34 PM
kirilik kirilik is offline
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Other Language - A problem with Lex

Hi,

I have some problem with Lex

if I write 1 + 1 I'm getting:
Found token INT ('1')
Found token OP ('+')
Found token INT ('1')

If I write 1+1 I'm getting:
Found token INT ('1')
Found token INT ('+1')

+1 is part of the language, what do I need to change so if I will write 1+1 I will get same as if I will write 1 + 1?

this is my regular expressions:
SIGN [+-]
DIGIT [0-9]
DIGIT_NZ [1-9]
INTEGER ([0])|(({SIGN}{0,1})({DIGIT_NZ}{1})({DIGIT}*))

Thanks

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Old November 18th, 2009, 07:23 PM
Twitch760 Twitch760 is offline
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Sounds like you need to ignore whitespace when you parse the string.

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Old November 19th, 2009, 04:45 PM
OmegaZero OmegaZero is offline
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You should not parse the sign with INTEGER and resolve this with your parser by having rule like

NUMBER ::= INTEGER | ADDOP INTEGER

Lex only deals with tokens in ignorance of the surrounding context. It can't tell when a '-' is a subtraction operator vs a unary negation (well you could have your parser screw around with the lexer mid-parse like perl does, but I don't even if that's possible in lex and in any case it would be horribly complicated).
__________________
sub{*{$::{$_}}{CODE}==$_[0]&& print for(%:: )}->(\&Meh);

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