Assembly help

I have done half, but don't know other half.
By looking at the comment, fill in the question marked filled.

org 100h
jmp START

_numberOperators EQU 7h
operatorString db ' +-*/^()' ;list of valid operators for IS_OPERATOR preceeded with a space

;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;…
;This infinite loop reads a one character symbol from the keyboard and echoes it to the screen.
;Then calls IS_OPERATOR to find if it is true(1) or false(0) that the symbol is an operator.
;The '1' or '0' rv is sent to the screen and the screen advances to a new line.
;Kill this infinite loop by clicking the window's x button

START:
mov ah, 07h ;Read symbol
int 21h ;from keyboard.
mov ah, 02h ;Echo
mov dl, al ;symbol
int 21h ;to screen

push dx ;Push argument. The previous "mov dl, al" moved symbol into dl.
call IS_OPERATOR ;Call IS_OPERATOR to find if input symbol is an operator.
pop dx ;This loads dl with rv (1 0r 0) to be echoed to screen.
mov ah, 02h ;Send rv
int 21h ;to screen

;Advance screen to new print line
mov ah, 02h
mov dl,0Dh
int 21h
mov dl,0Ah
int 21h

jmp START ;Jump to START of infinite loop
;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;…


;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;…
;IS_OPERATOR returns true(1) or false(0) that the input parameter is an operator
IS_OPERATOR Proc

;Push 3 registers subrtn will use.
push ax ;Stores the input char in al
push bx ;Used as subscript i in C++ version
push bp ;Stores sp

;???????? ;mov sp to bp

;??? ;mov argument (input char) to ax
;??? ;mov _numberOperators to bx
;??? ;mov input char to beginning of operatorString; in C++ operatorString[0]=symbol;

jmp WHILE_CONDITION
WHILE_TOP: ;loop to see if input is an operator
;??? ;in C++ i = i-1;
WHILE_CONDITION:
;cmp ??? ;check to see if the input is equal to one of the operators:
;j? ??? ;in C++ if (symbol != operators[i])goto WHILE_TOP;

;If bx=0, symbol wasn't found in the original initialization of the array and return 0 (equivalent to false).
;Else symbol was part of the original initialization of the array and set bx=1 (equivalent to true).
;cmp ???
;???
;??? ;set up to return 1 (the symbol is an operator).
END_IF:

;this line makes 0 into '0' and 1 into '1' so they will print to the screen in ascii
add bx,30h ;AFTER proving to me that your pgm works, remove this line

;??? ;mov bx (the rv) to the stack

;Restore registers subrtn used
;???
;???
;???
ret
IS_OPERATOR ENDP
;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;…

THE OUT PUT SHOULD LOOK LIKE THIS:
+1
-1
*1
/1
^1
<1
>1
00
10
20
30
40
50
60
70
80
90

Follow the advice in this post (most importantly, use code tags and be specific as to your problem).

And it's crossposted--You will get more useful responses if you read & follow this advice as well