$i = 34 ; $s = "S" + $i ?

hai all;
i need a help in doing this task.

i have a variable $i;
where $i = 12;

I want to get a string variable from this as
$s = "ABCD12";
where 12 is from $i and "ABCD" is a String.

i need to do

$s = "ABCD" + $i Like that..

where $s will become "ABCD12"..

please help me in doing this..

thanks in advance ...


vijay

$s = "ABCD$i";

or

$s = "ABCD".$i;