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  #1  
Old July 3rd, 2012, 12:26 PM
armbsu armbsu is offline
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What's wrong in my code?

Hello
I am trying to print values in an array using a for loop. However, it does not enter into the for loop for some reason. What's wrong? It prints 3 correctly as size of the array though.

if ($line[0] eq "directories")
{

my $i;
my $array_size=scalar @lines;
print $array_size;
for($i=1; $i eq $array_size; $i++)
{
print $line[1];

}
}
Thank you for any pointers!

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  #2  
Old July 3rd, 2012, 01:09 PM
FishMonger FishMonger is online now
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You have several problems:
1) you're intermixing 2 different arrays @line and @lines
2) the initialization of the loop is wrong
3) the print statement is referring to the second element in the @line array.

It should be:
Code:
if ($line[0] eq "directories") {
    my $array_size = @line;
    print $array_size;
    for my $i (1..$#line) {
        print $line[$i];
    }
}

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  #3  
Old July 3rd, 2012, 01:52 PM
Laurent_R Laurent_R is offline
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FishMonger has told you a lot about what's wrong.

Just an additional note:

Code:
for($i=1; $i eq $array_size; $i++)


This is wrong. $i and $array_size are numerical values, they should be compared with == not with eq, which is for comparing strings.

So if you really want yo use the C-style loop (which I do not recommend), it should be:

Code:
for($i=1; $i == $array_size; $i++)


Having said that, a for or foreach loop such as the one suggested by FishMonger is much better.

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  #4  
Old July 3rd, 2012, 02:45 PM
FishMonger FishMonger is online now
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$array_size is the number of elements, not the indexes. So instead of == it should be < because the number of elements is 1 grater than the last index.

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  #5  
Old July 3rd, 2012, 04:35 PM
Laurent_R Laurent_R is offline
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Yes, FishMonger, you are right, my mistake.

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