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  #1  
Old May 16th, 2000, 08:54 AM
pepweb pepweb is offline
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Hi,

why is this image not shown from mysql


printf("name: %s<br>n", mysql_result($result,0,"name"));(This is working)

php:

echo "<img src=images/" +$picture_name+ "><br>n";(link appears broken when returned!)

in mysql varchar $picture_name = 1.gif

1.gif is located on the webserver in my directory/images, so not stored in mysql, so i have to refer to the path as shown above.

can somebody help me?


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Old May 16th, 2000, 12:09 PM
rod k rod k is offline
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First, + is NOT the concatenation operator in PHP. Use . instead.

Second, you didn't pull the value of $picture_name from your query result set.

echo "<img src=images/".mysql_result($result,0,"picture_name")."<br>n";

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