PHP Development
 
Forums: » Register « |  User CP |  Games |  Calendar |  Members |  FAQs |  Sitemap |  Support | 
User Name:
Password:
Remember me

The Shed is going Social! Join us on FaceBook and Twitter and chime in on the conversation.

Go Back   Dev Shed ForumsProgramming LanguagesPHP Development

Reply
Add This Thread To:
  Del.icio.us   Digg   Google   Spurl   Blink   Furl   Simpy   Y! MyWeb 
Thread Tools Search this Thread Rate Thread Display Modes
 
Unread Dev Shed Forums Sponsor:
  #1  
Old April 10th, 2000, 10:34 AM
Abe Facciazzi Abe Facciazzi is offline
Junior Member
Dev Shed Newbie (0 - 499 posts)
 
Join Date: Apr 2000
Posts: 11 Abe Facciazzi User rank is Just a Lowly Private (1 - 20 Reputation Level) 
Time spent in forums: < 1 sec
Reputation Power: 0
I've made this script to query my database (done in MySql) via url:

<?php
$db = mysql_connect("localhost", "");
mysql_select_db("archive",$db);
$result = mysql_query("select * from mytable where ID= $ID",$db);
if ($myrow = mysql_fetch_array($result)) {
echo "<table border=1>n";
echo "<tr><td>Name</td><td>Position</td></tr>n";
do {
printf("<tr><td>%s %s</td><td>%s</tr>n", $myrow["fieldone"], $myrow["fieldtwo"], $myrow["fieldthree"]);
} while ($myrow = mysql_fetch_array($result));
echo "</table>n";
} else {
echo "Sorry, no records were found!";
}
?>

The only working field is ID (Unique,Primary). All the other filelds generete a query error. http://www.mysite.com/test.php?ID=34 works http://www.mysite.com/test.php?fieldone=pippo doesn't work.

Any help is appreciated!

Thanks in advance!

Abe

Reply With Quote
  #2  
Old April 10th, 2000, 11:37 AM
rod k rod k is offline
Apprentice Deity
Dev Shed Loyal (3000 - 3499 posts)
 
Join Date: Jul 1999
Location: Niagara Falls (On the wrong side of the gorge)
Posts: 3,237 rod k User rank is Private First Class (20 - 50 Reputation Level)rod k User rank is Private First Class (20 - 50 Reputation Level) 
Time spent in forums: 4 m 8 sec
Reputation Power: 17
Send a message via AIM to rod k
Look at your query. You are querying the column ID with the value $ID. If you don't pass a value for $ID then the query won't work. If you want to specify a field and a value you need to pass like this:

?fieldname=fieldone&value=pippo
or
?fieldname=ID&value=34
etc

and change your query to:

$result=mysql_query("select * from mytable where $fieldname=$value");

IOW, if you want to be able to search on any field you have to specify the field.

Reply With Quote
  #3  
Old April 10th, 2000, 01:24 PM
Abe Facciazzi Abe Facciazzi is offline
Junior Member
Dev Shed Newbie (0 - 499 posts)
 
Join Date: Apr 2000
Posts: 11 Abe Facciazzi User rank is Just a Lowly Private (1 - 20 Reputation Level) 
Time spent in forums: < 1 sec
Reputation Power: 0
Thanks for your time. I tried it with the very same results, which you can see at http://millennio.it/prova.php?field...emin&value=rana
Code is:
$result = mysql_query("select * from users where $fieldname=$value",$db);
The fact that is working only with the ID field makes me think that this kind of query can be done only with primary and/or unique fields. Could be that? If you're willing to help me out pleae tell me anything you need (my MySQL database structure, HTML code, etc.) and I'll provide. Thanks again for your time.

Reply With Quote
  #4  
Old April 10th, 2000, 01:31 PM
rod k rod k is offline
Apprentice Deity
Dev Shed Loyal (3000 - 3499 posts)
 
Join Date: Jul 1999
Location: Niagara Falls (On the wrong side of the gorge)
Posts: 3,237 rod k User rank is Private First Class (20 - 50 Reputation Level)rod k User rank is Private First Class (20 - 50 Reputation Level) 
Time spent in forums: 4 m 8 sec
Reputation Power: 17
Send a message via AIM to rod k
Sorry, my mistake. Since $value might contain non-numeric information it should have single quotes around it:

$result=mysql_query("select * from mytable where $fieldname='$value'");

Reply With Quote
  #5  
Old April 11th, 2000, 10:45 AM
Abe Facciazzi Abe Facciazzi is offline
Junior Member
Dev Shed Newbie (0 - 499 posts)
 
Join Date: Apr 2000
Posts: 11 Abe Facciazzi User rank is Just a Lowly Private (1 - 20 Reputation Level) 
Time spent in forums: < 1 sec
Reputation Power: 0
Well, it definitely worked! Thanks again very much for your support!

Reply With Quote
Reply

Viewing: Dev Shed ForumsProgramming LanguagesPHP Development > How do i pass a variable by url

Developer Shed Advertisers and Affiliates



Thread Tools  Search this Thread 
Search this Thread:

Advanced Search
Display Modes  Rate This Thread 
Rate This Thread:


Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

vB code is On
Smilies are On
[IMG] code is On
HTML code is Off
View Your Warnings | New Posts | Latest News | Latest Threads | Shoutbox
Forum Jump

Forums: » Register « |  User CP |  Games |  Calendar |  Members |  FAQs |  Sitemap |  Support | 
  
 


Powered by: vBulletin Version 3.0.5
Copyright ©2000 - 2013, Jelsoft Enterprises Ltd.

© 2003-2013 by Developer Shed. All rights reserved. DS Cluster - Follow our Sitemap