onerror ???

I'm trying to fix my script so that when an error arises I can print an error message

The error I'm trying to work around is not the type that shows an error message but rather the conditions are not right for the script and it prints out garbage.....

Hi,

Well what I understand is that you are looking for the way of printing the error?

If you have an arror while playing with MySQL stuff in the code try

print mysql_error();

after the line that has the error

Regards
Luis Tena
The Chile and Tortillas city, México

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Tnax