Parse error:syntax error, unexpected '/'

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November 28th, 2012, 01:19 AM

josephbupe

Contributing User

Join Date: Nov 2012

Posts: 56

Time spent in forums: 13 h 10 m 2 sec
Reputation Power: 1

PHP-General - Parse error:syntax error, unexpected '/'

Hi,

I am saving images into a folder and storing their names in the MySQL database. I need to fetch and display in a php webpage, but I am receiving an error:

Quote:

Parse error: syntax error, unexpected '/' in C:\Program Files\Abyss Web Server\htdocs\My MOVIES\showreport1.php on line 122

The following is part of the code I am trying to use:

Code:

$counter=0; while($row=mysql_fetch_array($result)) { 	$m_id=$row['m_id']; 	$mtitle=$row['mtitle']; 	$myear=$row['myear']; 	$mcountry=$row['mcountry']; 	$mgenres=$row['mgenres']; 	$filename=$row['mfilename'];	 	
} 	 	
if($counter>=0) 
{ 	
echo "<td valign=top>\n 	
<table width=340 border=1 align=left class=allborder> \n 	 	
<tr> \n 		
<td rowspan=4 colspan=3 class=topBorder> <? echo '<img src="./images/'.$row['mfilename'].'" width="90" height="120" alt="" />';  ?>\n 	</tr>\n 	<tr> \n 		
<td width=120> Title:  <td>$mtitle\n 	
</tr>\n 		
<tr> \n 		<td> Year:  <td> $myear\n 	</tr>\n 		<tr> \n 		<td> Country:  <td> $mcountry\n 	</tr>\n 	</tr>\n 		<tr> \n 		<td colspan=6 class=topBorder> <a href=viewdetail.php?m_id=$m_id>View Detail Info</a>\n 	</tr>\n 	</table>\n</td>\n

I will appreciate your help.

Joseph

November 28th, 2012, 02:16 AM

Timmeyy

Registered User

Join Date: Nov 2012

Posts: 18

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You tried to echo when your already in an echo. I've cleaned it up a bit for you, this might work better:

PHP Code:


		
			
echo  '

<td valign=top>      

<table width=340 border=1 align=left class=allborder>

<tr><td rowspan=4 colspan=3 class=topBorder><img src="./images/'.$row['mfilename'].'" width="90" height="120" alt="" />          </td> 

<tr><td width=120> Title:  <td>'.$mtitle.'      </tr>

<tr><td> Year:  <td> '.$myear.'</tr> ';

November 28th, 2012, 06:56 PM

BarryG

Contributing User

Join Date: Aug 2011

Location: Sydney Australia

Posts: 134

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Your html tag attribute values should be quoted.
Your array element needs to have { and } around it to tell php where the variable starts and ends.

PHP Code:


		
			
 $counter=0;

 while($row=mysql_fetch_array($result)) {

     $m_id=$row['m_id'];

     $mtitle=$row['mtitle'];

     $myear=$row['myear'];

     $mcountry=$row['mcountry'];

     $mgenres=$row['mgenres'];

     $filename=$row['mfilename'];         

}          

if($counter>=0) 

{     

    echo "<td valign=\"top\">     

    <table width=\"340\" border=\"1\" align=\"left\" class=\"allborder\">          

    <tr>         

    <td rowspan=\"4\" colspan=\"3\" class=\"topBorder\"> <img src=\"./images/{$row['mfilename']}\" width=\"90\" height=\"120\" alt=\"\" />

     </tr>

     <tr>         

    <td width=\"120\"> Title:  <td>$mtitle     

    </tr>         

    <tr>

    <td> Year:    <td> $myear

     </tr>

    <tr>

    <td> Country:    <td> $mcountry

     </tr>

     </tr> 

    <tr> 

    <td colspan=\"6\" class=\"topBorder\">    <a href=\"viewdetail.php?m_id=$m_id\">View Detail Info</a>

     </tr>

     </table>

    </td>";