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  #1  
Old December 23rd, 2012, 12:26 PM
phpstudent phpstudent is offline
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Php form

1. file.php

<html>
<body>

<?php
session_start();

$_SESSION['num1'] = mt_rand(1,5);
$q1 = $_SESSION['num1'] ;
echo "$q1";
$_SESSION['num2'] = mt_rand(6,20);
$q2 = $_SESSION['num2'] ;
?>

<form name="lab5" method="post" action="f2.php">

<table border=1 cellspacing=0 cellpading=0>

<tr> <td> Q1 </td> <td> <?php echo $q1 ?> * <?php echo $q2 ?> </td> <td> <input type = 'text' size = '2' name = one > </td> </tr>

<tr><td colspan=6 align='right'><input type='submit' value='Score' name='btn_score'></td></tr>


</table>

</form>

</body>
</html>

2. f2.php

<?php
session_start();
echo $_SESSION['num1'];
echo $_SESSION['num2'];

$UserV = $_POST['one'];

echo "userValue is $UserV";

$OneResult = $_SESSION['num1'] * $_SESSION['num2'] ;
echo "result is $OneResult " ;

?>


When i run file1.php, I get blank value for $userV after i enter a value.
but i get correct value for $oneresult.

How can i get the $UserV in f2 page?

Please help.

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  #2  
Old December 23rd, 2012, 12:52 PM
Rhytz's Avatar
Rhytz Rhytz is offline
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Posts: 102 Rhytz User rank is Sergeant Major (2000 - 5000 Reputation Level)Rhytz User rank is Sergeant Major (2000 - 5000 Reputation Level)Rhytz User rank is Sergeant Major (2000 - 5000 Reputation Level)Rhytz User rank is Sergeant Major (2000 - 5000 Reputation Level)Rhytz User rank is Sergeant Major (2000 - 5000 Reputation Level)Rhytz User rank is Sergeant Major (2000 - 5000 Reputation Level) 
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You have no apostrophes around the name value of your field
Code:
<input type = 'text' size = '2' name = one >


should be

PHP Code:
<input type='text' size='2' name='one' 

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  #3  
Old December 23rd, 2012, 12:52 PM
phpstudent phpstudent is offline
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Please disregard. I found my mistake.

Thanks.

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