Post with cURL

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November 2nd, 2012, 12:44 PM

jiceman

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[Resolved] Post with cURL

Hello,

I'm trying to post a file from the local server to a remote server. I'm using cURL to do so, but it's not working right.

PHP Code:


		
			
 $filename = '@'.getcwd()."/test.txt";

$vars[0] = "file=".urlencode($filename);

$vars[1] = "newName=".urlencode("success.txt");

$postString = implode('&', $getVars);



$url = "www.myserver.com/postProcess.php";



$ch = curl_init();

curl_setopt($ch,CURLOPT_URL, $url);

curl_setopt($ch,CURLOPT_POST, count($vars));

curl_setopt($ch,CURLOPT_POSTFIELDS, $poststring);

curl_setopt($ch,CURLOPT_RETURNTRANSFER, true);

$result = curl_exec($ch);

curl_close($ch);

From everything I've read, this ('@'.getcwd()."/test.txt") should be pulling the file and posting it to the external server.

a print_r($_POST) just gives me these results though...

Code:

Array ( [file] => @/var/www/html/test.txt [newName] => success.txt )

The actual file itself is not being sent, just the path

Thanks to anyone who can help me out.

Last edited by jiceman : November 5th, 2012 at 08:07 AM. Reason: problem solved

November 2nd, 2012, 12:46 PM

ManiacDan

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Quote:

From everything I've read, this ('@'.getcwd()."/test.txt") should be pulling the file and posting it to the external server.

Where did you read that? It's not true. Use file_get_contents to get a file's contents.

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November 2nd, 2012, 01:40 PM

jiceman

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Thank you Dan.
I read that the "@" symbol was supposed to tell cURL that what followed was a reference to a file on the local system, and to send that file during the post.

I'm trying to send a pdf file. The pdf file is 2 pages, and now I'm creating a blank 2 page pdf file.
I'm trying 2 different methods, but I get the same results of just a blank 2 page pdf.

PHP Code:


		
			
 $handle = fopen("files/test.pdf", 'a');

fwrite($handle, $_POST['file']);

fclose($handle);



file_put_contents("files/test2.pdf", $_POST['file']);

November 2nd, 2012, 01:50 PM

ManiacDan

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Oh man, I totally brain farted on @. Yes, that's correct.

This code should work:

$data['Filedata'] = "@".$file_path;
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, TRUE);
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_POSTFIELDS, $data);
$response = curl_exec($ch);
return $response;

POSTFIELDS needs to have a variable called 'Filedata'. you can't just stick it into the array.

And once it makes it to the posted script, it will be an actual file upload, not a regular POST field.

November 2nd, 2012, 03:24 PM

jiceman

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Dan, You're awesome. You are great help.
One last thing...

Is it possible to send the file like that and other variables as well, particularly an array.

So for example, what I was sending before (being unable to send the file) was something like this...

PHP Code:


		
			
 $vars['names'][] = "a";

$vars['names'][] = "b";

$vars['names'][] = "c";

$vars['names'][] = "d";

$vars['names'][] = "e";

$vars['file'] = "@/var/www/html/file.pdf";

I then turned that into a GET type string. (like this: "var=value&var2=value2&var3=value3")
On the target server, the $_POST variable would recreate the arrays as desired.
the only issue was that the file wouldn't get sent.

So now the file is being sent, but if my array is something like...

PHP Code:


		
			
 $vars['test'] = "test value";

$vars['names'][] = "a";

$vars['names'][] = "b";

$vars['names'][] = "c";

$vars['names'][] = "d";

$vars['names'][] = "e";

$vars['Filedata'] = "@/var/www/html/file.pdf";

And just the $vars is being posted in the POSTFIELDS instead of the string form,
Then the file does get posted like I wanted, but now the $_POST['names'] just equals the string "Array".
$_POST['test'] does equal "test value" though.

Is it possible to send the file, and data arrays, so that $_POST will recreate the arrays like it did before?

November 2nd, 2012, 05:06 PM

E-Oreo

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Yes, something like this should work:

PHP Code:


		
			
 $vars['names[0]'] = "a";

$vars['names[1]'] = "b";

$vars['names[2]'] = "c";

$vars['names[3]'] = "d";

$vars['names[4]'] = "e";

$vars['file'] = "@/var/www/html/file.pdf";

Comments on this post

ManiacDan agrees!

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November 5th, 2012, 08:06 AM

jiceman

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That makes sense now that I see it. Thank you E-Oreo.
It works perfectly.
Thanks again ManiacDan.

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