August 7th, 2013, 06:03 AM
How to render different button base on condition?
I have a question is how to create a button base on status. let say if not login, the button will direct to the login page, if not, the button will direct to the logout page. May i know how to do this in php? I hv the codes as below..
$LoginStatus = False;
$LoginStatus = True;
$loginname = "Guest";
August 7th, 2013, 06:57 AM
Please enclose your code in [ PHP ] tags. See the sticky at the top of this forum that says READ THIS BEFORE POSTING.
What have you tried and what is not working the way you want?
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August 7th, 2013, 07:32 AM
You shouldn't be relying on button values for logged in/out status. Any page which requires a login should check to see if the current user is logged in. If they're not, that page should redirect to a login page.
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