While command not working

I am having a problem trying to code a while statement into my PHP script.
I am using PHP-3.0.16.

I have created a PHP script to process up to 15 parameters to extract data from a LDAP database input via a HTML form.

I have the following code :-
<?php function process_form()
{
global $name
global $(the other 14 parameters)
}
?>

<?php
while (list($key,$value = each (HTTP_POST_Vars))
{
if {!empty($value))
if ((value)!=submit)
if ((value)!=results)

$PARAM=$PARAM.$key."=".$value;
}
.
.
.
<?php
if (empty($stage)){display_form();}
else {process_form();}
?>

$PARAM is processed using ldap_search.

If the script is as above, I get details from the LDAP database, but my blank form displays the warning
Variable passed to each() is not an array or object in /www/htdocs/php/seznam2.php3 on line 119. (line 119 is the while command).

If I include the while statement within the process_form function, my blank form is what I want to see ( ie without the warning), but
when I process the form I do not get anything back from the LDAP database and have the warning printed.

I have tried putting the while statement in its own function statement with the same result. The problem is that the HTTP_POST_VARS are not passed to the while statement.

Can anyone please let me know how to overcome this problem.

while (list($key,$value = each (HTTP_POST_Vars))


looks to me like you are missing a ")"

I have managed to resolve my coding problem with the help of Stew (from the PHPBUILDER mailing group)and a fresh set of eyes here.

The problem was that i needed to specify $HTTP_POST_VARS as a global within the function.

My process_form function now looks like this
<?php3 function process_form()
{
global $HTTP_POST_VARS;
while (list($key,$value) = each (HTTP_POST_VARS))
{
etc


Thanks to all those who took the time to look into my problem.

Tony