Accessing the next element

Text = open('Text.list','r').readlines()
for Line in Text :
# now i want to see if the current value of Line is equal to the
# next element in the file, ie. is Line == element[x+1]

#What do you mean by element?  How does an "element" differ from Line?
#this code compares pairs of lines without counters, at some memory
#cost.

# the names curtail and behead come from the j definitions
# http://www.jsoftware.com
# curtail=: }:
# behead=: }.
def curtail(LIST):
    '''
        >>> curtail([1,2,3])
        [1, 2]
    '''
    return LIST[:-1]

def behead(LIST):
    '''
        >>> behead([1,2,3])
        [2, 3]
    '''
    return LIST[1:]

# preferred file use.  Use the "with" statement.
with open('Text.list','r') as input_stream:
    Text = input_stream.readlines()

# compare pairs of lines
for (LINE,NEXTLINE,) in zip(curtail(Text),behead(Text)):
    if LINE == NEXTLINE:
        print('duplicate adjacent lines of\n"{}"'.format(LINE))

lastline = None
with open('Text.list','r') as Text:
    for Line in Text:
        if Line == lastline:
            # duplicate line found
            print "Duplicate line: ",line
        lastline = Line

'''list_get_duplicates1.py

create a list of duplicates in a given list
'''

def get_duplicate_items(mylist):
    """
    return a list of duplicate items in mylist
    """
    return [item for item in set(mylist) if mylist.count(item) > 1]


# testing ...
mylist1 = [ 'oranges' , 'apples' , 'oranges' , 'grapes' ]
mylist2 = list('abcdefgbd')

sf = 'Duplicates = %s'

print(mylist1)
print(sf % get_duplicate_items(mylist1))

print('-'*50)

print(mylist2)
print(sf % get_duplicate_items(mylist2))

'''result -->
['oranges', 'apples', 'oranges', 'grapes']
Duplicates = ['oranges']
--------------------------------------------------
['a', 'b', 'c', 'd', 'e', 'f', 'g', 'b', 'd']
Duplicates = ['b', 'd']
'''